c++-the difference between the value of the transmission and the reference

Difference between value passing and reference passing # include <iostream> #include <iomanip>using namespace std;void fiddle (int in1, int &in2) { in1 = in1 + 100;in2 = in2 + 100;cout << "the values are"; cout << SETW (5) << in1;cout << SETW (5) & lt;< in2 << Endl;} int main () {int v1 = 7, v2 = 12;cout << "The values are:"; cout << SETW (5) << v1;cout << setw (5) < ;< v2 << endl;fiddle (v1, v2); cout << "The values are:"; cout << SETW (5) << v1;cout << SETW (5) << v2 << endl;system ("pause"); return 0;}

Operation Result:

7 12

107 112

7 112

It can be concluded that wearing a reference will change the original value of the variable, and if the value is used in the function, it will not change its original value.

c++-the difference between the value of the transmission and the reference