Js date difference days we generally use the year, month, and day for addition and subtraction can be calculated, of course, you can also convert the date into a day millisecond and then add and subtract to convert, Next let's look at some examples.
1. Calculate the number of days when the two dates are different.
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Var s = (new Date (paramObj. end_date.replace (/-/g, "/")-(new Date (paramObj. start_date.replace (/-/g ,"/"))));
Var day = s/1000/60/60/24
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Example 2
Js inside can be directly Date1-Date2, and still converted to millisecond time difference calculation.
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// Calculate the number of days between two dates
Function DateDiff (sDate1, sDate2) {// The format of sDate1 and sDate2 is 2002-12-18
Var aDate, oDate1, oDate2, iDays
ADate = sDate1.split ("-")
ODate1 = new Date (aDate [1] + '-' + aDate [2] + '-' + aDate [0]) // convert to the 12-18-2002 format
ADate = sDate2.split ("-")
ODate2 = new Date (aDate [1] + '-' + aDate [2] + '-' + aDate [0])
IDays = parseInt (Math. abs (oDate1-oDate2)/1000/60/60/24) // converts the number of milliseconds to the number of days
Return iDays
}
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2. Calculate the date after a certain number of days
In JavaScript, calculate the date of the day after the day. It is far from convenient in. Net, and a function can solve the problem. This problem has plagued me for a while and finally solved the problem through a netizen's introduction. Post it and share it with you.
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<Script language = "javascript" type = "text/javascript">
Var startDate = new Date (); var intValue = 0;
Var endDate = null;
IntValue = startDate. getTime (); intValue + = 100*(24*3600*1000 );
EndDate = new Date (intValue );
Alert (endDate. getFullYear () + "-" + (endDate. getMonth () + 1) + "-" + endDate. getDate ());
</Script>
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The above 100 represents the date after 100 days. You can modify it. In JS, Date. getTime () can only be the Date after 1970.01.01, and the month is 0-11, which is a little different. Don't worry. Of course, you can also calculate the date after a specific date.
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<Script language = "javascript" type = "text/javascript">
Var startDate = new Date (2007, (8-1), 1, 10, 10 );
Var intValue = 0;
Var endDate = null;
IntValue = startDate. getTime (); intValue + = 100*(24*3600*1000 );
EndDate = new Date (intValue );
Alert (endDate. getFullYear () + "-" + (endDate. getMonth () + 1) + "-" + endDate. getDate ());
</Script>
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If none of the above calculate the leap year, the following instance is complete.
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// Determine whether it is a leap year
Function isLeapYear (year ){
If (year % 4 = 0 & (year % 100! = 0) | (year % 400 = 0 )))
{
Return true;
}
Return false;
}
// Judge the two dates before and after
Function validatePeriod (fyear, fmonth, fday, byear, bmonth, bday ){
If (fyear <byear ){
Return true;
} Else if (fyear = byear ){
If (fmonth <bmonth ){
Return true;
} Else if (fmonth = bmonth ){
If (fday <= bday ){
Return true;
} Else {
Return false;
}
} Else {
Return false;
}
} Else {
Return false;
}
}
// Calculate the difference between the two dates
Function dateDiff (d1, d2 ){
Var disNum = compareDate (d1, d2 );
Return disNum;
}
Function compareDate (date1, date2)
{
Var regexp =/^ (d {1, 4}) [-|.] {1} (d {1, 2}) [-|.] {1} (d {1, 2}) $ /;
Var monthDays = [,];
Regexp. test (date1 );
Var date1Year = RegExp. $1;
Var date1Month = RegExp. $2;
Var date1Day = RegExp. $3;
Regexp. test (date2 );
Var date2Year = RegExp. $1;
Var date2Month = RegExp. $2;
Var date2Day = RegExp. $3;
If (validatePeriod (date1Year, date1Month, date1Day, date2Year, date2Month, date2Day )){
FirstDate = new Date (date1Year, date1Month, date1Day );
SecondDate = new Date (date2Year, date2Month, date2Day );
Result = Math. floor (secondDate. getTime ()-firstDate. getTime ()/(1000*3600*24 ));
For (j = date1Year; j <= date2Year; j ++ ){
If (isLeapYear (j )){
MonthDays [1] = 2;
} Else {
MonthDays [1] = 3;
}
For (I = date1Month-1; I <date2Month; I ++ ){
Result = result-monthDays [I];
}
}
Return result;
} Else {
Alert ('Sorry, the first time must be earlier than the second time. Thank you! ');
Exit;
}
}
Call this function to pass two time values: 2013-01-19 2013-12-19 Days = dateDiff (d1, d2 ); |
