Calculation of interest on "C-language" deposit

Calculation of interest on deposits. There are 1000 yuan, want to save 5 years, according to the following 5 ways to Save://1, one deposit 5 years. 2, the first deposit 2 years, after the expiry of the principal and interest to save 3 years. 3, the first deposit 3 years, after the expiry of the principal and interest to save 2 years. 4, deposit 1-year period, after the expiry of the principal and interest after the 1-year period, the continuous deposit 5 times. 5, deposit current account. Current interest is settled once every quarter. 1-Year periodic interest: 4.14%;//2 periodic interest: 4.68%;//3 periodic interest: 5.4%;//5-year periodic interest: 5.85%;//Demand deposit interest: 0.72%; (demand deposit is settled once per quarter interest)//r--annual interest rate n--deposit years//1 years of this and: P = 1000* (1+r);//n-year principal and interest and: P = 1000* (1+n*r);//n/a 1-year deposit and principal: P = 1000* (1+r) ^n;//current deposit and interest: P = 1000* (1+R/4) ^4n--a quarter of interest and interest and #inclu  De <stdio.h> #include <math.h>int main () {double p1,p2,p3,p4,p5;double p0 = 1000.0;double R1 = 0.0414;double R2  = 0.0468;double R3 = 0.054;double R4 = 0.0585;double Huo = 0.0072;P1 = P0 * (1 + 5 * R4);p 2 = (P0 * (1 + 2 * r2)) *  (1 + 3 * R3);p 3 = (P0 * (1 + 3 * r3)) * (1 + 2 * r2);p 4 = P0 * POW ((1 + R1), 5);p 5 = p0 * POW (1 + HUO/4 );p rintf ("One deposit 5 years:%f\n", p1);p rintf ("Deposit 2 years, after maturity will be the principal and interest again 3 years:%f\n", p2);p rintf ("Deposit 3 years, after the expiry of the principal and interest again 2 years:%f\n", p3);p rintf ( "Deposit 1 years, after the expiry of the principal and interest to save 1 years, 5 consecutive times:%f\n", p4);p rintf ("Deposit current deposits. Current interest is settled quarterly:%f\n ", p5); return 0;} 

Calculation of interest on "C-language" deposit