The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem:you ' ve got an array of n elements (the elements of the array is Inde Xed starting from 1); Also, there is Q-queries, each of the defined by a pair of integers li, ri (1?≤?li?≤?ri?≤?n). You need to find for each query the sum of elements of the array with indexes from Li to RI, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a-a-the-makes the sum of query replies Maxi Mum possible. Your task is to find the value of this maximum sum.
Input
The first line contains, space-separated integers n (1?≤?n?≤?2 105) and Q (1?≤?q?≤?2 105)-the number of elements in t He array and the number of queries, correspondingly.
The next line contains n space-separated integers ai (1?≤?ai?≤?2 105)-the array elements.
Each of the following Q lines contains, space-separated integers li and ri (1?≤?li?≤?ri?≤?n)-the i-th query.
Output
In a single, line print a, integer-the maximum sum of query replies after the array elements is reordered.
%lld specifier to read or write 64-bit integers inс++. It is preferred to use the CIN, cout streams or the%i64d specifier.
Sample Test (s)
Input
3 3
5 3 2
1 2
2 3
1 3
Output
25
Input
5 3
5 2 4) 1 3
1 5
2 3
2 3
Output
33
Greedy, to count the number of occurrences of each position, and then of course, the largest number of places where the most, and then multiply the line
/************************************************************************* > File name:cf-169-c.cpp > Aut Hor:alex > Mail: [email protected] > Created time:2015 April 02 Thursday 15:11 23 Seconds ******************************* *****************************************/#include <functional>#include <algorithm>#include <iostream>#include <fstream>#include <cstring>#include <cstdio>#include <cmath>#include <cstdlib>#include <queue>#include <stack>#include <map>#include <bitset>#include <set>#include <vector>using namespace STD;Const DoublePI =ACOs(-1.0);Const intINF =0x3f3f3f3f;Const DoubleEPS =1e-15;typedef Long LongLL;typedefPair <int,int> PLL;Static Const intN =200100;intSum[n];intArr[n];intMain () {intN, Q; while(~scanf("%d%d", &n, &q)) {memset(Sum,0,sizeof(sum)); for(inti =1; I <= N; ++i) {scanf("%d", &arr[i]); }intL, R; while(q--) {scanf("%d%d", &l, &r); ++SUM[L]; --sum[r +1]; } for(inti =1; I <= N; ++i) {Sum[i] + = sum[i-1]; } sort (sum +1, Sum + n +1); Sort (arr +1, arr + n +1); LL ans =0; for(inti = n; I >=1; -i) {ans + = (LL) arr[i] * Sum[i]; }printf("%i64d\n", ans); }return 0;}
Codeforces Round #169 (Div. 2)---C. Little Girl and Maximum Sum (simple greedy)