Pagination online already useful ASP to the article content pagination display code, I also did not use the time to study in detail. Published a few very long articles today, in order to facilitate the browsing of netizens, only to set the heart to write the following code. Because our program is written by C#.net, about C # Such examples, the information on the Internet can not be found; so had to start analysis from the program structure, a little program but spent half a day to complete, shame! Deficiencies, please advise, what better way to tell.
Show Content section:
Defining variables
int i,start,stop,t,stat,statt,pp,pagecount,pagesize;
Variable initial value
stat=0;
statt=0;
start=0;//the string position of the start query, initially 0
Stop=0;
pagesize=2000;//defines at least the number of strings displayed per page
pagecount=0;
Get the current number of pages
pa=request.params["Page"];
if (pa== "" | | pa==null)
Pa= "1";
Pp=convert.toint32 (PA);
Get content
articletxt=rs["Contenttxt"]. ToString ();
Determines whether the content length of a page is greater than the number of strings displayed per page defined
if (articletxt. Length>=pagesize)//If greater than the number of strings, then we can page to display
{
T=articletxt. length/pagesize;//get roughly the total number of pages
Based on the number of page loops currently available
for (i=0;i<t;i++)
{
If the query starts at a range beyond the length of the entire content, you don't have to look for breakpoints (page points);
if (start+pagesize<articletxt. Length)
{
Stat=articletxt. IndexOf ("</P>", start+pagesize)//Find </P> location of page points
if (stat<=0)//If not found
Stat=articletxt. IndexOf ("</p>", start+pagesize);//Find </p> the location of the paging point; Here you can set your own page-point judgment
}
if (stat<=0)//If the page is not found, the description can not be paged, there is no need to do other labor; otherwise, do pagination
articletext=articletxt;//the result to the variable to be exported
Else
{
stop=stat;//the location of the paging point as the end of the page
if (start+pagesize>=articletxt. Length)//If the starting position is beyond the length of the entire content, the end of the page is the end of the content
Stop=articletxt. Length;
if (pp==i+1)//If is current, then output the contents of the current page
Articletext=articletxt. Substring (Start,stop-start);//Fetch the starting position of the content to the end position this string output
start=stat;//the end position as the starting position for the next page
pagecount++;//Get actual page totals
}
}
}
Pagination section (it's much simpler here)
String html;//defines a paging code variable
if (pagecount>1)///When the number of pages is greater than 1 we show the number of pages
{
for (i=1;i<=pagecount;i++)
{
if (I==PP)//If is the current page, bold display
html+= "<b>[" +i+ "]</b>";
Else
html+= "<a href=?id=" +articleid+ "&page=" +i+ ">[" +i+ "]</a>";
}
if (Pp+1>pagecount)//shows the next page for easy browsing
html+= "<a href=?id=" +articleid+ "&page=" + (PageCount) + ">[next page]</a></p>";
Else
html+= "<a href=?id=" +articleid+ "&page=" + (pp+1) + ">[next page]</a></p>";
}
You can add the above code to try! If you have any questions, please post it to the Net People forum, address: http://bbs.wrclub.net
