Differences between phpif () {} And if ()

I encountered this problem when I was studying PHP today. {Code...} shows the result {code...} does not show the result. Isn't the code at both ends the same? I encountered this problem when I was studying PHP today.

Function filter ($ fun) {for ($ I = 0; $ I <= 100; $ I ++) {if (call_user_func_array ($ fun, array ($ I ))) continue; echo $ I."
";}}// Calculate the divisible function one ($ num) {return $ num % 3 = 0;} // flip the string function two ($ num) {return $ num = strrev ($ num);} filter ("one"); echo"
"; Filter ('two ');

Display result

Function filter ($ fun) {for ($ I = 0; $ I <= 100; $ I ++) {if (call_user_func_array ($ fun, array ($ I ))) {continue; echo $ I."
";}}// Returns the divisible function one ($ num) {return $ num % 3 = 0;} // flip the string function two ($ num) {return $ num = strrev ($ num);} filter ("one"); echo"
"; Filter ('two ');

The result is not displayed. Isn't the code at both ends the same?

Reply content:

I encountered this problem when I was studying PHP today.

Function filter ($ fun) {for ($ I = 0; $ I <= 100; $ I ++) {if (call_user_func_array ($ fun, array ($ I ))) continue; echo $ I."
";}}// Calculate the divisible function one ($ num) {return $ num % 3 = 0;} // flip the string function two ($ num) {return $ num = strrev ($ num);} filter ("one"); echo"
"; Filter ('two ');

Display result

Function filter ($ fun) {for ($ I = 0; $ I <= 100; $ I ++) {if (call_user_func_array ($ fun, array ($ I ))) {continue; echo $ I."
";}}// Returns the divisible function one ($ num) {return $ num % 3 = 0;} // flip the string function two ($ num) {return $ num = strrev ($ num);} filter ("one"); echo"
"; Filter ('two ');

The result is not displayed. Isn't the code at both ends the same?

    for($i=0; $i<=100; $i++){                       if(call_user_func_array($fun, array($i)))                            continue;                            echo $i."
";                   }

Equivalent

    for($i=0; $i<=100; $i++){                       if(call_user_func_array($fun, array($i))){                            continue;                       }                       echo $i."
";                   }

Whether it is true or not, php will be executed. php is not python. It is not to say that indentation is a statement block.

Php's if is the same as C's if.

If you do not increase the brackets, you can use semicolons (;). Braces (_) are added to the braces.

for($i=0; $i<=100; $i++){                       if(call_user_func_array($fun, array($i))){                            continue;                            echo $i."
";                          }                }

This program is wrong, becauseecho $i."
";Will never be executed

if(true){}:

phpIf (true) {// the code in the curly braces will be executed}

Whileif(true):

phpIf (true) echo (233); // only this echo (233); it belongs to if to judge echo time ();

The difference isif(true)Only the following sentence must be followed: the condition is that the Code is actually executed, andif(true){}The code in the curly braces of is the Execution Code with a condition, andCan be empty