Brute force matching _java of Java pattern matching

Brute-Force match for Java pattern matching

/** * Pattern matching brute force matching/package javay.util;  /** * Pattern Match Brute-force * @author DBJ/public class PMBF {/** * match Brute-force * @param Target Target String * @param pattern Mode String * @return mode string for the first occurrence in the target string/public static int Patternmatch (String target, St
    Ring pattern) {int targetlength = Target.length ();
    int patternlength = Pattern.length (); int idxtgt = 0; The position of the character in the target string int idxptn = 0; The position of the character in the pattern string int index = 0;
      Saves the position of the starting character of ING with the pattern string while (Idxtgt < targetlength && IDXPTN < Patternlength) {//Find a matching character
        if (Target.charat (idxtgt) = = Pattern.charat (IDXPTN)) {//If equal, continue the subsequent comparison of characters idxtgt + +;
      IDXPTN + +;
        else {//otherwise the target string begins with the second character to compare Index + + with the first character of the pattern string;
        IDXPTN = 0;
      IDXTGT = index;
    }///Match to one, output result if (IDXPTN = = patternlength) {//Description match successful return index;
    else {return-1;
 }
  }
}

Use examples:

static int indexOf (char[] source,char[] Target {char-I
    = target[0];
    int max = (source.length-target.length);
    for (int i = 0; I <= max; i++) {/* Look for the
      character/
      if (Source[i]!= a) {while ++i
        Max && Source[i]!= A;
      /* Found-character, now look at the rest of V2
      /if (i <= max) {
        int j = i + 1;
        int end = j + target.length-1;
        for (int k = 1; J < end && Source[j] = = Target[k]; j + +, k++);
        if (j = = end) {/
          * Found whole string. */Return
          i
    }}} return-1;
  }

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