Decimal number to n binary C + + implementation

write an algorithm that converts a non-negative decimal integer N to another b -ary integer that has a base of b .

#include <iostream>

#include <string.h>

using namespace Std;

The desired decimal-to - B -binary function

void Shift (int b,int before)

{

Char B_num[b];

if (b<10) {for (int i=0;i<b;i++) b_num[i]=i+48;}

Else

{

for (int i=0;i<b;i++) b_num[i]=i+48;

for (int j=10;j<b;j++) b_num[j]= ' A ' +j-10;

}//defines the symbol for each position that is greater than ten

String result= "";

int N;int m;

while (BEFORE>=B)

{

n=before/b;

M=before%b;

RESULT+=B_NUM[M];

Before=n;

}

Result+=b_num[n];

cout<< " converted successfully , The result is :" <<endl;

for (int i=result.length () -1;i>=0;i--) cout<<result[i];

cout<<endl;

}

int main ()

{

L:int Num;int B;

cout<< " to convert decimal numbers to how many binary numbers ?" <<endl;

cin>>b;

cout<< " Please enter raw data " <<endl;

cin>>num;

Shift (B,num);

Goto L;

return 0;

}

The experimental results are as follows:

Decimal number to n binary C + + implementation