Oracle Exercise SQL statement exercises

Source: Internet
Author: User

Table (i) Student (student table)

Property name

Data type

Can be empty

Meaning

Sno

VARCHAR2 (3)

Whether

Study number (main code)

Sname

VARCHAR2 (8)

Whether

Student Name

Ssex

VARCHAR2 (2)

Whether

Student Sex

Sbirthday

Date

Can

Student's date of birth

Class

VARCHAR2 (5)

Can

Students in the same class

CREATE TABLE Student

(

Sno VARCHAR2 (3) NOT NULL,

Sname VARCHAR2 (8) NOT NULL,

Ssex VARCHAR2 (2) NOT NULL,

Sbirthday Date,

Class VARCHAR2 (5)

)

;

Comment on column student. Sno

Is ' study number ';

Comment on column student. Sname

Is ' student name ';

Comment on column student. Ssex

Is ' student sex ';

Comment on column student. Sbirthday

Is ' student birth date ';

Comment on column student. Class

Is ' Student's class ';

Table (ii) Course (curriculum)

Property name

Data type

Can be empty

Meaning

Cno

VARCHAR2 (5)

Whether

Course Number (main code)

Cname

Varchar (10)

Whether

Course Name

Tno

VARCHAR2 (3)

Whether

Faculty Number (external code)

CREATE TABLE Course

(

Cno VARCHAR2 (5) NOT NULL,

Cname varchar (TEN) is not NULL,

Tno VARCHAR2 (3) NOT NULL

)

;

Comment on column course.cno

Is ' Course number ';

Comment on column course.cname

Is ' course name ';

Comment on column Course.tno

Is ' faculty number ';

ALTER TABLE Course

Add constraint Pk_course primary key (Cno);

ALTER TABLE Course

Add constraint Fk_tno foreign key (Tno)

References Teacher (Tno);

Table (iii) score (score table)

Property name

Data type

Can be empty

Meaning

Sno

VARCHAR2 (3)

Whether

School Number (external code)

Cno

VARCHAR2 (5)

Whether

Course number (outside code)

Degree

Number (4,1)

Can

Results

Main code: sno+ Cno

CREATE TABLE Score

(

Sno VARCHAR2 (3) NOT NULL,

Cno VARCHAR2 (5) NOT NULL,

Degree Number (4,1)

)

;

Comment on column Score.sno

Is ' study number ';

Comment on column score.cno

Is ' Course number ';

Comment on column Score.degree

is ' performance ';

ALTER TABLE Score

Add constraint Fk_sno foreign key (Sno)

References student (SNO);

ALTER TABLE Score

Add constraint Fk_cno foreign key (Cno)

References Course (Cno);

Table (iv) Teacher (Teacher's table)

Property name

Data type

Can be empty

Meaning

Tno

VARCHAR2 (3)

Whether

Faculty Number (main code)

Tname

VARCHAR2 (4)

Whether

Faculty Name

Tsex

VARCHAR2 (2)

Whether

Faculty Sex

Tbirthday

Date

Can

Faculty Birth date

Prof

VARCHAR2 (6)

Can

Title

Depart

Varchar (10)

Whether

Faculty Department

CREATE TABLE TEACHER

(

TNO VARCHAR2 (3) NOT NULL,

Tname VARCHAR2 (4) NOT NULL,

Tsex VARCHAR2 (2) NOT NULL,

Tbirthday DATE,

Prof VARCHAR2 (6),

Depart VARCHAR2 (TEN) NOT NULL

)

Comment on column Teacher.tno

Is ' faculty number ';

Comment on column teacher.tname

Is ' faculty name ';

Comment on column teacher.tsex

Is ' faculty gender ';

Comment on column Teacher.tbirthday

Is ' Faculty of birth ';

Comment on column teacher.prof

is ' title ';

Comment on column Teacher.depart

Is ' faculty Department ';

ALTER TABLE TEACHER

Add constraint Pk_tno primary key (Tno)

Table 1-2 data in the database

Table (i) Student

Sno

Sname

Ssex

Sbirthday

Class

108

Zenghua

Man

1977-09-01

95033

105

Kuanming

Man

1975-10-02

95031

107

Wang Li

Woman

1976-01-23

95033

101

Li June

Man

1976-02-20

95033

109

Wang fang

Woman

1975-02-10

95031

103

Contacts

Man

1974-06-03

95031

INSERT into Student values (' 108 ', ' Zeng Hwa ', ' Male ', to_date (' 1977-09-01 ', ' yyyy-mm-dd '), ' 95033 ');

INSERT into Student values (' 105 ', ' Kuanming ', ' Male ', to_date (' 1975-10-02 ', ' yyyy-mm-dd '), ' 95031 ');

INSERT into Student values (' 107 ', ' Wang Li ', ' Female ', to_date (' 1976-01-23 ', ' yyyy-mm-dd '), ' 95033 ');

INSERT into Student values (' 101 ', ' Li June ', ' Male ', to_date (' 1976-02-20 ', ' yyyy-mm-dd '), ' 95033 ');

INSERT into Student values (' 109 ', ' Wang Fang ', ' Female ', to_date (' 1975-02-10 ', ' yyyy-mm-dd '), ' 95031 ');

INSERT into Student values (' 103 ', ' contacts ', ' Male ', to_date (' 1974-06-03 ', ' yyyy-mm-dd '), ' 95031 ');

Table (ii) Course

Cno

Cname

Tno

3-105

Introduction to Computers

825

3-245

Operating system

804

6-166

Digital circuit

856

9-888

Advanced mathematics

831

INSERT into Course values (' 3-105 ', ' Introduction to Computer ', ' 825 ');

INSERT into Course values (' 3-245 ', ' operating system ', ' 804 ');

INSERT into Course values (' 6-166 ', ' digital circuit ', ' 856 ');

INSERT into Course values (' 9-888 ', ' Advanced math ', ' 831 ');

Table (iii) score

Sno

Cno

Degree

103

3-245

86

105

3-245

75

109

3-245

68

103

3-105

92

105

3-105

88

109

3-105

76

101

3-105

64

107

3-105

91

108

3-105

78

101

6-166

85

107

6-166

79

108

6-166

81

INSERT into score values (' 108 ', ' 6-166 ', ' 81 ');

Table (iv) Teacher

Tno

Tname

Tsex

Tbirthday

Prof

Depart

804

Sung

Man

1958-12-02

Associate professor

Computer Department

856

Zhang Xu

Man

1969-03-12

Lecturer

Department of Electronic Engineering

825

Wang ping

Woman

1972-05-05

Ta

Computer Department

831

Liu Bing

Woman

1977-08-14

Ta

Department of Electronic Engineering

INSERT into Teacher values (' 804 ', ' sung ', ' Male ', to_date (' 1958-12-02 ', ' yyyy-mm-dd '), ' associate Professor ', ' computer Department ');

INSERT into Teacher values (' 856 ', ' Zhang Xu ', ' Male ', to_date (' 1969-03-12 ', ' yyyy-mm-dd '), ' lecturer ', ' Electronic Engineering Department ');

INSERT into Teacher values (' 825 ', ' Wang Ping ', ' female ', to_date (' 1972-05-05 ', ' yyyy-mm-dd '), ' ta ', ' computer Department ');

INSERT into Teacher values (' 831 ', ' Liu Bing ', ' Female ', to_date (' 1977-08-14 ', ' yyyy-mm-dd '), ' ta ', ' Electronic Engineering Department ');

1. Query the sname, Ssex, and class columns of all records in the student table.

Select Sname,ssex,class from student;

2, the inquiry teacher all units namely does not duplicate depart column.

SELECT DISTINCT * from student;

3. Query all records of student table.

SELECT * from Student;

4. Query all records from 60 to 80 of the scores in the score table.

SELECT * from score where degree > degree < 80;

5. Check the record of 85, 86 or 88 in the score table.

SELECT * FROM score where degree = or degree = or degree = 88;

6, inquires the student table "95031" class or the sex is "the female" the classmate record.

SELECT * from Student where CLASS = 95031 or SSEX = ' female ';

7. Query the student table for all records in descending order of class.

SELECT * FROM student order BY class Desc;

8, in CNO Ascending, Degree descending query score all records of the table.

SELECT * FROM Score ORDER by CNO ASC, Degree desc;

9. Check the number of students in "95031" class.

Select Class,count (1) as quantity from student where class = ' 95031 ' Group by class;

10. Check the student number and course number of the highest score in the score table. (sub-query or sort)

Select Sno | | CNO as study number and course number from score order by degree Desc;

11. Check the average score of each course.

Select Cno,count (1) as number, AVG (degree) as average from score group by Cno;

12. Check the average score of the course with at least 5 students enrolled in the score table and begin with 3.

Select Cno,count (1) as number, AVG (degree) as average from score where Cno like ' 3% ' GROUP by Cno have Count (Cno) >5;

13, the query score is greater than 70, less than 90 of the SNO column.

SELECT * from score where degree between and 90;

14. Sname, CNO and degree columns for all students are queried.

Select S.sname,c.cno,c.degree from student S, score C where S.sno=c.sno;

15. Check the SNO, CNAME and degree columns of all students.

Select C.sno,q.cname,c.degree from student S, score c,course Q where S.sno=c.sno and q.cno=c.cno;

16. Check the sname, CNAME and degree columns of all students.

Select S.sname,q.cname,c.degree from student S, score c,course Q where S.sno=c.sno and q.cno=c.cno;

17. Check the average score of "95033" class students.

Select Class,avg (degree) as average from student S,score C where s.sno=c.sno and class = ' 95033 ' Group by class;

18. Assume that a grade table is created using the following command:

CREATE table Grade (Low number (3), UPP number (3), rank char (1))

Insert into grade values (90,100, ' A ');

Insert into grade values (80,89, ' B ');

Insert into grade values (70,79, ' C ');

Insert into grade values (60,69, ' D ');

Insert into grade values (0,59, ' E ');

The SNO, CNO and rank columns of all students are now queried.

Select S.sno,s.cno,g.rank from score s, Grade G where s.degree between G.low and G.upp;

Oracle Exercise SQL statement exercises

Related Article

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.