Python + django implements simple file upload,
Today, we will share a small example of simple File Upload implemented by Django.
Procedure
• Create a Django project and a Django Application
• Design Model
• Processing urls. py and views. py
• Design templates and Design Forms
• Run the project and view the database
Next let's complete each small part separately.
Create a project and an application
Django-admin startproject Django_upload
Django-admin startapp app
Add a directory named upload, which will be used later.
Then remember to add 'app' to INSTALLED_APPS in settings. py ',. Pay attention to the comma ~~
Design Model
To upload a file, you must know who uploaded the file and what it was uploaded. Therefore, our model is simple, with a user name and a file name. The following app. models. py
from __future__ import unicode_literalsfrom django.db import models# Create your models here.# User CLass for user,username and userimg pathclass NormalUser(models.Model): username = models.CharField(max_length=30) headImg = models.FileField(upload_to='./upload') def __unicode__(self): return self.username class Meta: ordering = ['username']
After the model is created, synchronize the database. The command is simple. Because my Django version is 1.9.6
Python manage. py syncdb is unavailable
We can use the following command to replace
Python manage. py makemigrations
Python manage. py migrate
Urls. py and views. py
These two files exist to implement the V and C of the MVC model.
Views. py is as follows:
from django.shortcuts import render,render_to_responsefrom django import formsfrom django.http import HttpResponsefrom app.models import *# Create your views here.class NormalUserForm(forms.Form): username = forms.CharField() headImg = forms.FileField()def registerNormalUser(request): if request.method == "POST": uf = NormalUserForm(request.POST,request.FILES) if uf.is_valid(): # get the info of the form username = uf.cleaned_data['username'] headImg = uf.cleaned_data['headImg'] # write in database normalUser = NormalUser() normalUser.username = username normalUser.headImg = headImg normalUser.save() return HttpResponse('Upload Succeed!') else: uf = NormalUserForm() return render(request,'register.html',{'uf':uf})
Urls. py
"""Django_upload URL ConfigurationThe `urlpatterns` list routes URLs to views. For more information please see: https://docs.djangoproject.com/en/1.9/topics/http/urls/Examples:Function views 1. Add an import: from my_app import views 2. Add a URL to urlpatterns: url(r'^$', views.home, name='home')Class-based views 1. Add an import: from other_app.views import Home 2. Add a URL to urlpatterns: url(r'^$', Home.as_view(), name='home')Including another URLconf 1. Import the include() function: from django.conf.urls import url, include 2. Add a URL to urlpatterns: url(r'^blog/', include('blog.urls'))"""from django.conf.urls import urlfrom django.contrib import adminfrom app.views import *urlpatterns = [ url(r'^admin/', admin.site.urls), url(r'^register/$',registerNormalUser),]
Generally, we create a super Administrator with the following command:
Python manage. py createsuperuser
Then follow the prompts to create it.
Design templates and forms
As a matter of fact, we can see a class named NormalUserForm in views. py just now. Its significance is to conveniently retrieve the form data we need from the request. I'm afraid you have noticed that the NormalUserForm field is the same as that of the NormalUser model. Learn each other's philosophies :-)
Templates/register.html
<!DOCTYPE html>There are three important points:
• <Form method = "POST" enctype = "multipart/form-data">:The specific format of the Form. Make sure that enctype is specified when uploading data.• {% Csrf_token % }:For cross-origin requests, we need to add the template tag inside the form tag, and use render instead of render_to_response in views. py to implement
• {Uf. as_p }}:With the. as_p method, django outputs all fields of the form on the template page according to the default style.
Debug and enable the application
Well, most of the tasks are done. Let's open our development server to verify it.
Python manage. py runserver
Open the browser and enter http: // 127.0.0.1: 8000/register
Then enter the form as required. When the is_valid () method is added, views. py will automatically help us verify the form data fields!
Open our database management software and you will find that only the path is stored, not the real data. This also reflects the core concept of big data storage. Click the upload directory and find that the file has been uploaded successfully!
Summary
Although this small example is very simple today, there are many things worth pondering. My gains are as follows.
• Use models. FileField () to implement the File Upload Component• Add a form class for the corresponding model, with the same fields. This makes it easier to obtain form data. Uf = NormalUserForm (request. POST, request. FILES ).
• Form output on the html page in the form enctype format and. as_p Mode
That's it!
The above is all the content of this article. I hope it will be helpful for your learning and support for helping customers.
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