First, about the split and join methods
1 is processed only for strings. Split: Split string, join connection string
2.string.join (Sep): Combines all elements of Sep (string representations) into a new string, using string as a separator
3.string.split (str= ", Num=string.count (str)): delimited by str, the character slices a string, and if NUM has a specified value, only the NUM substring is delimited.
4. Os.path.splie ()/os.path.join () on the Import OS module seems to be a different processing mechanism, but functionally identical.
Second, Split () method
The information after help is as follows:
Split (...)
S.split ([Sep [, Maxsplit]]), List of Stringsreturn a list of the words in the string S, using Sep as Thedelimiter stri Ng. If Maxsplit is given, at the most maxsplitsplits be done. If Sep is no specified or is None, anywhitespace string is a separator.
Chinese translation:
Split (...)
S.split ([Sep [, Maxsplit]]), a list of strings divided into
Returns a set of lists that are formed by using a separator (SEP) Split string. If you specify the maximum number of splits, the end is the maximum split. If the delimiter is not specified or is none, the delimiter defaults to a space.
Instance:
S= ' a b C ' Print s.split (') st= ' Hello World ' print st.split (' o ') print st.split (' O ', 1)
--------Output---------
[' A ', ' B ', ' C ']
[' Hell ', ' w ', ' Rld ']
[' Hell ', ' World ']
Os.path.split ()
Os.path.split is separated by the path of the file name and path, such as D:\\python\\python.ext, can be divided into [' D:\\python ', ' Python.exe '], the example is as follows:
Import Osprint os.path.split (' C:\\Program File\\123.doc ') print Os.path.split (' C:\\Program file\\ ')----------------- Output---------------------(' C:\\Program file ', ' 123.doc ') (' C:\\Program file ', ')
Three joins ()
A= ' ABCD ' print '. Join (a) print ' | '. Join ([' A ', ' B ', ' C ']) #可以把 [' A ', ' B ', ' C '] as a= ' ABCD '; Join ({' A ': 1, ' B ': 2, ' C ': 3, ' d ': 4})
Note: '. ' Wait for the delimiter to concatenate all the elements (strings) in the join into a new string through the delimiter
Maybe someone like me, the definition of String.Join () Love dead, abruptly to [' A ', ' B ', ' C '] first converted to a string, and then in the join
Such as:
B=str ([' A ', ' B ', ' C ']) print ' | '. Join (b)
I thought it was a positive solution, but otherwise. The output is: [| ' | a| ' |,| | b| ' |,| | C| ' |], and the cause of the inconsistency with the above is the lily, the [' A ', ' B ', ' C '] into a string, in Python, we found that the string, Ganso, list They are sequence types, have the same access, you can access the following index elements.
The above can be knocked again to try again.
Input:
Output:
A.b.c.da|b|ca.c.b.dos.path.join (path1[,path2[,......]) Os.path.join (path1[, path2[, ...])
#将多个路径组合后返回, the parameters before the first absolute path are ignored. >>> os.path.join (' c:\\ ', ' csv ', ' test.csv ') ' C:\\csv\\test.csv ' >>> os.path.join (' Windows\Temp ', ' C : \ \ ', ' csv ', ' test.csv ') ' C:\\csv\\test.csv ' >>> os.path.join ('/home/aa ', '/home/aa/bb ', '/home/aa/bb/c ') '/ Home/aa/bb/c '