Python: Converting an XML format file into a JSON-formatted file

Since JSON-formatted files are highly convenient to work with and produce a large number of XML-formatted files every day, there is a need to convert XML-formatted files into JSON-formatted files.
Directly below the code, there are two versions, according to the requirements of the free choice:

#!/usr/bin/python# -*- coding: utf-8 -*-#Function:Xml_To_Json#version 1.0#Author: Herman#需要用到的两个模块import xmltodict; import json;#定义函数def pythonXmlToJson():    with  open(‘filename.xml‘, ‘r‘) as f:        xmlStr = f.read()    convertedDict = xmltodict.parse(xmlStr);    jsonStr = json.dumps(convertedDict, indent=1);    print jsonStr;#执行函数if __name__=="__main__":    pythonXmlToJson();

#!/usr/bin/python# -*- coding: utf-8 -*-#Function:Xml_To_Json#version 1.1#Author: Herman#Date: 2018-06-01#Usage: python Xml_To_Json.py xmlfile_dir >> tar_dirimport xmltodict;import json;import sys;def pythonXmlToJson():    with  open(sys.argv[1], ‘r‘) as f:        xmlStr = f.read()    convertedDict = xmltodict.parse(xmlStr);    jsonStr = json.dumps(convertedDict, indent=1);    print jsonStr;if __name__=="__main__":    pythonXmlToJson();

The difference between the two versions is obvious, the first lacks flexibility, the second uses a similar position variable in the shell to make the Python script more flexible.

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Python: Converting an XML format file into a JSON-formatted file