Python creates a dictionary without too many quotes.
This example describes how to create a dictionary without too much reference in python. Share it with you for your reference. The specific implementation method is as follows:
1. Use the itertools Module
import itertoolsthe_key = ['ab','22',33]the_vale = ['aaaa',"dddddddd",'22222222222']d = dict(itertools.izip(the_key,the_vale))print d
2. Add Parameters
dict = dict(red = 1,bule = 2,yellow = 3)print dict
Result: {'yellow': 3, 'bucket': 2, 'red': 1}
3. Use built-in zip Functions
Zip ([iterable,...]) returns a list,
the_key = ['ab','22',33]the_vale = ['aaaa',"dddddddd",'22222222222']dict2 = dict(zip(the_key,the_vale))print type(zip(the_key,the_vale))print dict2
Result:
<type 'list'>{33: '22222222222', 'ab': 'aaaa', '22': 'dddddddd'}
4. fromkeys function of dict
Each created key has the same value.
fromkeys(seq[,value])Create a new dictionary with keys from seq and values set to value.the_key = ['ab','22',33]the_vale = 0d = dict.fromkeys(the_key,the_vale)print
Result: {33: 0, 'AB': 0, '22': 0}
import stringcount_by_letter = dict.fromkeys(string.ascii_lowercase,0)print count_by_letter
Result:
{'a': 0, 'c': 0, 'b': 0, 'e': 0, 'd': 0, 'g': 0, 'f': 0, 'i': 0, 'h': 0, 'k': 0, 'j': 0, 'm': 0, 'l': 0, 'o': 0, 'n': 0, 'q': 0, 'p': 0, 's': 0, 'r': 0, 'u': 0, 't': 0, 'w': 0, 'v': 0, 'y': 0, 'x': 0, 'z': 0}
I hope this article will help you learn Python programming.
How to Create a dictionary in a python dictionary
Create temporary variables
Tmp = dict ()
Tmp. setdefault ('b1 ', 'abc ')
AB ['a3 '] = tmp
Which dictionary method can connect two dictionaries together python
There is an update () method, but if the key is the same, the latter's key-value will overwrite the former.
D. update (E, ** F)-> None. Update D from dict/iterable E and F.
If E has a. keys () method, does: for k in E: D [k] = E [k]
If E lacks. keys () method, does: for (k, v) in E: D [k] = v
In either case, this is followed by: for k in F: D [k] = F [k]
Example:
>>> A = {3: 5, 4: 6}
>>> B = {4: 8, 7: 9}
>>> A. update (B)
>>>
{3: 5, 4: 8, 7: 9}