Python string substitution, regular lookup substitution

Source: Internet
Author: User

ImportReif __name__=="__main__": URL="\ deded<a href =""> This is the first link </a><a href =""> This is a second link </a> \ n"    #remove \ none = Url.replace ("\ n","")    #Remove both spacesboth =One.strip ()#The regular match Re.match matches from the beginning of the string. three = Re.match (r"(<a ([^>]*?) >) (. *?) (</a>)", both)ifThree is  notNone:arr=three.groups ()Print(Arr[0] +"hahaha"+ arr[3])    #The regular lookup contains </a>,re.search to find the entire string, as long as it matches. Re.match is searched from the string, if there is no match at the beginning, it is not consideredresult = Re.search ("</a>", both). Group ()Print(Result)#regular Find and replace    Print(Re.sub (Re.compile (R"<a.*?</a>", Re. S),"", both))

Python string substitution, regular lookup substitution

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