[Help] PHP two-dimensional array to remove specific duplicate values original array: $ arr & nbsp; array (id & nbsp; & gt; & nbsp; 1, name & nbsp; & gt; & nbsp; aaa, uid & gt; 1), & nbsp; array (id & nbsp; & gt; & nbsp; 2, name & nbsp; & [help] PHP two-dimensional array to remove specific duplicate values
Original array:
$ Arr = array (
Array ('id' => 1, 'name' => 'AAA', 'uid' => 1 ),
Array ('id' => 2, 'name' => 'BBB ', 'uid' => 2 ),
Array ('id' => 3, 'name' => 'CCC ', 'uid' => 3 ),
Array ('id' => 4, 'name' => 'ddd ', 'uid' => 4 ),
Array ('id' => 5, 'name' => 'CCC ', 'uid' => 3 ),
Array ('id' => 6, 'name' => 'BBB ', 'uid' => 2 ),
Array ('id' => 7, 'name' => 'BBB ', 'uid' => 2 ),
Array ('id' => 8, 'name' => 'fff', 'uid' => 6 ),
Array ('id' => 9, 'name' => 'CCC ', 'uid' => 3 ),
Array ('id' => 10, 'name' => 'BBB ', 'uid' => 2 ),
Array ('id' => 11, 'name' => 'ddd ', 'uid' => 4 ),
Array ('id' => 12, 'name' => 'Eee ', 'uid' => 5 ),
Array ('id' => 13, 'name' => 'fff', 'uid' => 6 ),
);
Problem Description: to obtain the values of id, and 9 in $ arr, but the values of 'name' and 'uid' cannot be the same. Example: name = ccc for id = 3, but name = ccc for id = 5, take the next value of id = 6. if id = 6 is the same as the previous one, take the next one, and so on.
If you want to get the value of id 1, 3, 5, 7, 9, the expected result is:
$ Arr_new = array (
Array ('id' => 1, 'name' => 'AAA', 'uid' => 1 ),
Array ('id' => 3, 'name' => 'CCC ', 'uid' => 3 ),
Array ('id' => 6, 'name' => 'BBB ', 'uid' => 2 ),
Array ('id' => 8, 'name' => 'fff', 'uid' => 6 ),
);
Recursive PHP two-dimensional array values
Share :? 1, 'name '? =>? 'AAA', 'uid' => 1 ),? Array ('id '? =>? 2, 'name '? => ?... 'Data-pics = ''>
------ Solution --------------------
This is the method of algorithm processing. if there is a problem, the algorithm will traverse the data that has been obtained and obtain the next one if it is found. The purpose of this algorithm is to count the number of people and post more posts only. to solve this problem, you only need to comment out the code that traverses the data of the current query.
------ Solution --------------------
What does this mean?
$arr = array(
array('id' => 1,'name' => 'aaa','uid'=>1),
array('id' => 2,'name' => 'bbb','uid'=>2),
array('id' => 3,'name' => 'ccc','uid'=>3),
array('id' => 4,'name' => 'ddd','uid'=>4),
array('id' => 5,'name' => 'ccc','uid'=>3),
array('id' => 6,'name' => 'bbb','uid'=>2),
array('id' => 7,'name' => 'bbb','uid'=>2),
array('id' => 8,'name' => 'fff','uid'=>6),
array('id' => 9,'name' => 'ccc','uid'=>3),
array('id' => 10,'name' => 'bbb','uid'=>2),
array('id' => 11,'name' => 'ddd','uid'=>4),
array('id' => 12,'name' => 'eee','uid'=>5),
array('id' => 13,'name' => 'fff','uid'=>6),
);
$id = array(1,3,5,7,9);
foreach($arr as $v) $a[$v['id']] = $v;
$t = array();
foreach($id as $k) {
if(! in_array($a[$k]['name'], $t)) {
$res[] = $a[$k];
$t[] = $a[$k]['name'];
}else {
for($i=$k+1; $i
if(! in_array($a[$i]['name'], $t)) {
$res[] = $a[$i];
$t[] = $a[$i]['name'];
break;
}
}
}
print_r($res);
Array
(
[0] => Array
(
[Id] => 1
[Name] => aaa
[Uid] => 1
)
[1] => Array
(
[Id] => 3
[Name] => ccc
[Uid] => 3
)
[2] => Array
(
[Id] => 6
[Name] => bbb
[Uid] => 2