Php parses the json string from HTMLpost

Php parses the json string from HTMLpost. I convert a json object into a json string in js, and then submit it to php in an implicit input.
This is the HTML part.

The string obtained in php is:

[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]

String Processing

$ Json_string = $ _ POST ['json']; $ json = htmlspecialchars_decode ($ json_string); print_r (json_decode ($ json); // The result is null.

Change

$ Json = stripslashes (htmlspecialchars_decode ($ json_string); print_r (json_decode ($ json); // The result is still null.

Change it.

$ Json = stripslashes (htmlspecialchars_decode ($ json_string); print_r (json_decode ($ json); // well, the result is still blank.

Reply to discussion (solution)

It's really hard for you to do so complicated coding.

$s = '[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';$s = html_entity_decode($s);$s = stripslashes($s);print_r(json_decode($s, 1));

Array(    [0] => Array        (            [table] => a            [field] => value            [max] => 60            [min] =>         ))

$str='[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';$new=htmlspecialchars_decode($str);$new=str_replace('\\','',$new);$new1=json_decode($new,true);echo "
";print_r($new1);echo "
";

Array
(
[0] => Array
(
[Table] =>
[Field] => value
[Max] => 60
[Min] =>
)

)

It's really hard for you to do so complicated coding.

$s = '[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';$s = html_entity_decode($s);$s = stripslashes($s);print_r(json_decode($s, 1));

Array(    [0] => Array        (            [table] => a            [field] => value            [max] => 60            [min] =>         ))

Or not.
However, in php, I directly write $ json_string = '[{\ "table \": \ "a \", \ "field \\": \ "value \", \ "max \": 60, \ "min \": null}] '; yes, is the data in POST different?

$str='[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';$new=htmlspecialchars_decode($str);$new=str_replace('\\','',$new);$new1=json_decode($new,true);echo "
";print_r($new1);echo "
";

Array
(
[0] => Array
(
[Table] =>
[Field] => value
[Max] => 60
[Min] =>
)

)

This method has been tried, and there is nothing wrong, just if you

$s = '[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';

Change

$s=$_POST['json'];

No.
The problem is that the POST data,
However, when JavaScript eval is used in HTML to convert the string into a json object, the line feed is normal.

Echo base64_encode ($ _ POST ['json']);
Post result

Base64_encode and then echo

W3tcXCZhbXA7cXVvdDt0YWJsZVxcJmFtcDtxdW90OzpcXCZhbXA7cXVvdDtlcHFcXCZhbXA7cXVvdDssXFwmYW1wO3F1b3Q7ZmllbGRcXCZhbXA7cXVvdDs6XFwmYW1wO3F1b3Q7c3RhbmQ0XFwmYW1wO3F1b3Q7LFxcJmFtcDtxdW90O21heFxcJmFtcDtxdW90Ozo2MCxcXCZhbXA7cXVvdDttaW5cXCZhbXA7cXVvdDs6bnVsbH1dW10=W10=

Echo base64_encode ($ _ POST ['json']);
Post result

I have read the base64 encoding and decoding. I need to use html_entity_decode twice. thank you, moderator. thank you, James.

What we can see in HTML is:

But when it comes to PHP, it becomes

[{\\"table\\":\\"epq\\",\\"field\\":\\"stand4\\",\\"max\\":60,\\"min\\":null}]

(Echo output to html is not visible & quot)
So html_entity_decode is required twice.

$s = 'W3tcXCZhbXA7cXVvdDt0YWJsZVxcJmFtcDtxdW90OzpcXCZhbXA7cXVvdDtlcHFcXCZhbXA7cXVvdDssXFwmYW1wO3F1b3Q7ZmllbGRcXCZhbXA7cXVvdDs6XFwmYW1wO3F1b3Q7c3RhbmQ0XFwmYW1wO3F1b3Q7LFxcJmFtcDtxdW90O21heFxcJmFtcDtxdW90Ozo2MCxcXCZhbXA7cXVvdDttaW5cXCZhbXA7cXVvdDs6bnVsbH1dW10=W10=';$s = base64_decode($s);$s = str_replace('\\', '', $s);$s = html_entity_decode($s);$s = html_entity_decode($s);echo $s, PHP_EOL;print_r(json_decode(substr($s, 0, -4), 1));

[{"table":"epq","field":"stand4","max":60,"min":null}][]?Array(    [0] => Array        (            [table] => epq            [field] => stand4            [max] => 60            [min] =>         ))

Let's see what's going on.
In fact, this general debugging should be mastered

Let's see what's going on.
In fact, this general debugging should be mastered

Thank you!
I haven't used PHP for a long time, and I have never learned the system. many of them haven't.