HDU1985: Conversions

Problem Description
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

 

 

Input
The first line of input contains a single integer N, (1 ≤ N ≤1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. the unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

 

Output
For each dataset, you shoshould generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

 

Sample Input
5
1 kg
2 l
7 lb
3.5 GB
0 l

Sample Output
1 2.2046 lb
2 0.5284g
3 3.1752 kg
4 13.2489 l
5 0.0000 GB

 

Daily Necessities

 

[Cpp]
# Include <stdio. h>
# Include <string. h>
 
Int main ()
{
Int t;
Double n, m;
Char str [20];
Scanf ("% d", & t );
For (int I = 1; I <= t; I ++)
{
Scanf ("% lf % s", & n, str );
If (! Strcmp (str, "kg "))
{
M = n * 2.2046;
Printf ("% d %. 4lf lb \ n", I, m );
}
Else if (! Strcmp (str, "g "))
{
M = n * 3.7854;
Printf ("% d %. 4lf l \ n", I, m );
}
Else if (! Strcmp (str, "lb "))
{
M = n * 0.4536;
Printf ("% d %. 4lf kg \ n", I, m );
}
Else if (! Strcmp (str, "l "))
{
M = n * 0.2642;
Printf ("% d %. 4lf g \ n", I, m );
}
}
 
Return 0;
}

# Include <stdio. h>
# Include <string. h>

Int main ()
{
Int t;
Double n, m;
Char str [20];
Scanf ("% d", & t );
For (int I = 1; I <= t; I ++)
{
Scanf ("% lf % s", & n, str );
If (! Strcmp (str, "kg "))
{
M = n * 2.2046;
Printf ("% d %. 4lf lb \ n", I, m );
}
Else if (! Strcmp (str, "g "))
{
M = n * 3.7854;
Printf ("% d %. 4lf l \ n", I, m );
}
Else if (! Strcmp (str, "lb "))
{
M = n * 0.4536;
Printf ("% d %. 4lf kg \ n", I, m );
}
Else if (! Strcmp (str, "l "))
{
M = n * 0.2642;
Printf ("% d %. 4lf g \ n", I, m );
}
}

Return 0;
}