How do two arrays form a new array based on the same addition?

How to add two arrays to form a new Array $ t1 = Array & nbsp; (& nbsp; [0] & nbsp ;=& gt; & nbsp; 1320 & nbsp; [1] & nbsp ;=& gt; & nbsp; 990 & nbsp; [2] & nbsp ;=& gt; & nbsp; 895 & nbsp; [3] & nbsp; = & gt; & nbsp; 790 & nbs: How do two arrays form a new array based on the same addition?
$ T1 = Array ([0] => 1320 [1] => 990 [2] => 895 [3] => 790 [4] => 775 [5] => 745 [6] => 740 [7] => 680 [8] => 665 [9] => 535)
$ T2 = Array ([0] => Nanchang [1] => Ganzhou [2] => Ji 'an [3] => Jiujiang [4] => Nanchang [5] => jiujiang [6] => Pingxiang [7] => outside the province [8] => Nanchang [9] => Jiujiang)

You can create a $ t11 = record value,
$ T22 = This is the recorded region.
This ensures that the data is overwritten without duplicate names, but you do not know whether the calculation can be done in this way.

$ T11 = Array ([0] => 2760 [1] => 990 [2] => 895 [3] => 2070 [4] => 740 [5] => 680)
$ T22 = Array ([0] => Nanchang [1] => Ganzhou [2] => Ji 'an [3] => Jiujiang [4] => Pingxiang [5] => outside the province)

The calculated result is shown above .. Remove the same t2, and add the key names in t1. Share :? 1320? [1]? =>? 990? [2]? =>? 895? [3]? =>? 790? [4]? =>? 775? [5]? =>? 745? [6]? =>? 7 .. 'data-pics = ''>
------ Solution --------------------
Creating an array first is the result of removing duplicates from the $ t2 array (t22)

Loop this new array (t22), for each place name, go to the loop $ t2 array. if the two values are the same, take the key corresponding to $ t2 to $ t1 and add it to a new array ($ t11) (The current loop of the new array), and continue until every $ t2 sub-element in the current cycle of t22 is compared.
Continue to complete the $ t22 loop