How does PHP list a date from the current date?

For example, $ aa & quot; 2013-12-25 & quot; $ bbtime (); I want to list the month array (12) {[1] & amp; gt; string (6) & quot; 2013-12 & quot; [2] & amp; gt; string (6) & quot; 2014-1 & quot; [3] & amp; gt; string (6) & quot; 2014-2 & quot; [4] & amp; gt; string (6) & quot; 2014-3 & quot; [5] For example
$ Aa = "2013-12-25 ";
$ Bb = time ();
I want to list the months between and 12

Array (12 ){
[1] = & gt; string (6) "2013-12"
[2] => string (6) "2014-1"
[3] => string (6) "2014-2"
[4] => string (6) "2014-3"
[5] => string (6) "2014 -...."
}

Currently, only the current month of the current year can be listed.
For ($ I = 1; $ I <= date ('M'); $ I ++ ){
$ Dates [$ I] = date ('Y-'. $ I, strtotime (date ("Y-m-d ")));
}

Reply content:

For example
$ Aa = "2013-12-25 ";
$ Bb = time ();
I want to list the months between and 12

Array (12 ){
[1] = & gt; string (6) "2013-12"
[2] => string (6) "2014-1"
[3] => string (6) "2014-2"
[4] => string (6) "2014-3"
[5] => string (6) "2014 -...."
}

Currently, only the current month of the current year can be listed.
For ($ I = 1; $ I <= date ('M'); $ I ++ ){
$ Dates [$ I] = date ('Y-'. $ I, strtotime (date ("Y-m-d ")));
}

Let's start with your thoughts.

• This problem is used to "know how many cycles are a little difficult ".whileWill make the logic clearer
• Strtotime kill
• PHP4.3 +
• // My code is short and clear, hum

php// Http://3v4l.org/vuef4function monthtoday ($ past, $ now, $ format = 'Y-m') {$ current = strtotime (date ('y m-1 ', strtotime ($ past); $ result = array (); while ($ current <$ now) {$ result [] = date ($ format, $ current ); $ current = strtotime ('+ 1 month', $ current);} // contains the current month $ result [] = date ($ format, $ current); return $ result ;} print_r (monthtoday ('2017-12-25 ', time (); die;

Timestamp offset

   $monthDiffed) {        $m = $month;        $month = $monthDiffed;        $monthDiffed = $m;    }    $monthDiffed = $monthDiffed->modify("last day of -1 month");    $month = $month->modify("first day of +1 month");    $result = array();    while($month <= $monthDiffed) {        $result[] = $month->format( $format );        $month = $month->modify("+1 month");    }    return $result;}print_r( diffMonth("2014-6") );print_r( diffMonth("2014-6", "Y/m", "2013-6") );

$ Aa = "2003-02-25"; $ bb = date ("Y-m-d", time (); function datediffage ($ before, $ after) {$ B = getdate ($ before); $ a = getdate ($ after); $ y = $ m = 0; if ($ a ['mon'] = 1) {// for June 1, January, borrow year $ y = $ a ['Year']-$ B ['Year']-1; $ m = $ a ['mon']-$ B ['mon'] + 12 ;} else {if ($ a ['mon']> = $ B ['mon'] + 1) {// after the month, the monthly offset is $ y = $ a ['Year']-$ B ['Year']; $ m = $ a ['mon']-$ B ['mon']-1;} else {// after the month is borrowed, the month is reduced to negative, borrow year $ y = $ a ['Year']-$ B ['Year']-1; $ m = $ a ['mon']-$ B ['mon'] + 12-1 ;}$ datearr = array (); $ totalm = ""; if ($ y> 0) {$ totalm = $ y * 12; // if the value is greater than one year, it is converted to the monthly number of copies} $ totalm + = $ m; for ($ I = 0; $ I <$ totalm; $ I ++) {array_push ($ datearr, date ("Y-m", mktime (0, 0, 0, $ B ['mon'] + $ I, $ d, $ B ['Year']);} return $ datearr;

}

Print_r (datediffage (strtotime ($ aa), strtotime ($ bb )));

Circle code from: http://my.oschina.net/u/223350/blog/293687
Thanks to the original author for the modification.

echo (new DateTime('2013-12'))->diff(new DateTime(date('Y-m')))->format('%y year %m month %d days');

The result is that it has been several months and days since the target time.

Year x12 + month = past few months

$date = new DateTime('2013-12');$now = date('Ym');$months = array();while ($date->format('Ym')<=$now) {    array_push($months, $date->format('Y-m'));    $date->modify('+1 month');}print_r($months);

Obtain the month details from the target time to the present.

$ Aa = '2017-12-25 ';
$ A = strtotime ($ aa );
$ B = array ();
While ($ $ B [] = date ('Y-m', $ );
$ A = strtotime ('+ 1 month', $ );
}
Var_dump ($ B );

After writing, I found that the idea is similar to that of mcfog.

This problem seems to be all wrong,
If the time difference comes out, do you calculate for a month based on 28 days, or 30 days or 31 days?
Is the year calculated by 365 days or 366 days?