The original question is as follows:
Exercise 4.9 gives a positive integer of no more than 5 bits,
1. It is a number of digits;
2. Output each digit separately;
3. Output the figures in reverse.
Thinking: 1. require a positive integer with no more than 5 bits
2. To remove the number of each digit in the 5-bit
3. To be able to recognize the number of the first few digits.
Errors are made when the number of each digit is then converted into ASCII characters.
The error code is:
A= (char) k/10000; k=k%10000; b= (char) k/1000; k=k%1000; C= (char) k/100; k=k%100; D= (char) K/10; E= (char) k%10;
The result is always not getting the correct characters.
After debugging, it is found that the resulting 0-bit, is a null character. Only to be cast with (char) , the No. 0 character is obtained, not the character ' 0 '. Therefore, modify the code to:
A= (char) (k/10000+48); k=k%10000; B= (char) (k/1000+48); k=k%1000; C= (char) (k/100+48); k=k%100; D= (char) (k/10+48); E= (char) (k%10+48);
After the whole code is attached:
/****************************************************** Practice 4.9 give a positive integer of no more than 5 bits, ask for 1. It is a number of digits; 2. output each digit separately; 3. Output numbers in reverse. CREATE----------------------------by: idooi liutime: 2015/ 09/18-1046----------------------------------******************************************************/#include <stdio.h> #include <stdlib.h>int main (void) { int integer; int k; //for Value int grade; //indicates a few digits char a, b, c, d, e; //a= million, b= thousand, C= Hundred, d= 10, e= do{ printf ("Please Intput your number:\n "); &nbSP;&NBSP;&NBSP;&NBSP;SCANF ("%d", &integer); }while (integer>99999 | | integer<=0); k=integer; a= (char) (k/10000+48); k=k% 10000; b= (char) (k/1000+48); k=k%1000; c= (char) (k/100+48); k=k%100; d= (char) (k/10+48); e= (char) (k%10+48); if (a!= ' 0 ') { printf ("%d is a five-digit ", integer); grade=5; } else if (b!= ' 0 ') { printf ("%d is four digits \ n", integer); grade=4; } else if (c!= ' 0 ') { printf ("%d is three digits \ n", integer); grade=3; } else if (d!= ' 0 ') { printf ("%d is double-digit \ n", integer); grade=2; } else{ printf ("%d is single digit \ n", integer); grade=1; } switch (grade) { case 1: printf ("%c\n", e);p rintf ("%c\n", e);break; case 2: printf ("%c%c\n", d,e);p rintf ("%c%c\n", E , D); break; case 3: printf ("%c%c%c\n", C,D,E); printf ("%c%c%c\n", e,d,c); break; case 4: printf ("%c%c%c%c\n", B,C,D,E);p rintf ("%c% C%c%c\n ", e,d,c,b); break; case 5: printf ("%c%c%c %c%c\n ", a,b,c,d,e);p rintf ("%c%c%c%c%c\n ", e,d,c,b,a); break; } return 0;}
How numbers are converted to ASCII characters--rectification C after lesson 4.9