How to distinguish between Python and C + + (update ...) ）

There are many differences between Python and C + +, some of which are easily overlooked and cause a program error. Here is a list of some, for everyone's reference. Continuous update ...

Python does not have a self-increment decrement operator

There are ++i, i++ 、--i, I--。 Python does not have these operators. A common loop for C/s + + is:

for (int i = 0; i < ++i) {    std::cout << i << Endl;}

and the python corresponding loop is:

For I in range:    print (i)

Perhaps this is one of the important reasons that Python does not provide the self-increment decrement operator: there is no such common use case. If you really need to, most of the cases can be replaced with i + = 1,i-=.

Note that although Python does not support the + + operator, ++i does not error. ++i is interpreted as + (+ (i)).

>>>> i = 3>>> ++i3>>> i++syntaxerror:invalid syntax

implicit return of a Python function A common error in C + +: "Not all control paths return a value". If any of the paths do not return a value, an error is found.

Error:not all control Paths Returnsint F (bool flag) {    if (flag)    {        return 1;    }}

but the corresponding Python program does not have any problems:

def f (flag):    If flag:        return 1>>> print (f (True)) >>> 1>>> print (f (False)) >> > None

Although Python does not error, it is recommended that you explicitly return None if the function has a return value. This way, other people will not be confused when they see this code: Does the author mean to rely on an implicit return to return none, or to forgetA value of return?

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How to distinguish between Python and C + + (update ...) ）