How to handle one character at a time in Python

There are four ways to handle strings with one character at a time:

1. Use list to convert strings to characters;

2. For loop, traversing each character of the string;

3. Use the form of a collection +for loop to iterate through each character of the string;

4. Using map, passing function names, and strings, traversing each character of the processing string;

Gets a collection of all the characters in the string (go Heavy), using sets. Set (String) method.

The code is as follows:

#-*-Coding:utf-8-*-  
      
#====================  
#File: printexercise.py  
#Author: Wendy  
#Date: 2014-03-02  
#====================  
      
#eclipse pydev, python2.7 "'  
      
process one character at a time '
      
thestring =" I Love you! "
      
#转换为单个字符, returns the collection  
thelist = List (thestring)  
print (thelist)  
      
def Love (c):  
    u = c.upper () #大写转换  
    print (' {0} '. Format (u)), #不换行 return  
    u  
      
#遍历每个字符进行处理 for  
C in thestring: Love  
    (c)  
print ( "")  
      
#返回集合  
results = [Love (c) for C in TheString]  
print (results)  
      
#返回集合  
results_map = Map (Love, TheString)  
print (results_map)  
      
#去掉重复的字母, seek intersection  
import sets  
search = sets. Set ("Good morning!") #去掉重复的字母  
object = sets. Set ("What Are you Dong?")  
Print (search) print (  
object)  
print ('. Join (Search&object) #拼接字符串

Output:

[' I ', ' ', ' l ', ' o ', ' V ', ' e ', ', ' y ', ' o ', ' u ', '! ']  
I   L o V E   Y o U!   
I   L o V E   Y o U! [' I ', ' ', ' L ', ' o ', ' V ', ' E ', ', ' Y ', ' o ', ' U ', '! ']  
I   L o V E   Y o U! [' I ', ' ', ' L ', ' o ', ' V ', ' E ', ', ' Y ', ' o ', ' U ', '! ']  
Set (['! '), ', ' d ', ' G ', ' I ', ' M ', ' o ', ' n ', ' G ', ' R ']  
Set ([' A ', ', ', ' e ', ' d ', ', ' g ', ' h ', ' o ', ' n ', ' R ', ', ', ', ', ', ', ', ', ', ', W ', ' y ', '? ']  
 Dgonr

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