This article mainly introduces how to merge two dictionaries (dict) in Python. it is a very practical technique in Python programming, for more information about how to merge two dictionaries (dict) in Python, see the following example. The specific method is as follows:
Two existing dictionaries, dict, are as follows:
dict1={1:[1,11,111],2:[2,22,222]}dict2={3:[3,33,333],4:[4,44,444]}
Merge the two dictionaries to get a similar result:
{1:[1,11,111],2:[2,22,222],3:[3,33,333],4:[4,44,444]}
Method 1:
dictMerged1=dict(dict1.items()+dict2.items())
Method 2:
dictMerged2=dict(dict1, **dict2)
Method 2 is equivalent:
dictMerged=dict1.copy()dictMerged.update(dict2)
Or:
dictMerged=dict(dict1)dictMerged.update(dict2)
Method 2 is much faster than method 1. the timeit test is as follows:
$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged1=dict(dict1.items()+dict2.items())' 10000 loops, best of 3: 20.7 usec per loop$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged2=dict(dict1,**dict2)' 100000 loops, best of 3: 6.94 usec per loop$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged3=dict(dict1)' 'dictMerged3.update(dict2)' 100000 loops, best of 3: 7.09 usec per loop$ python -m timeit -s 'dict1=dict2=dict((i,i) for i in range(100))' 'dictMerged4=dict1.copy()' 'dictMerged4.update(dict2)' 100000 loops, best of 3: 6.73 usec per loop
I hope this article will help you with Python programming.