REPLACE % 0A with NULL. this is a normal Replacement. now I need to REPLACE multiple codes at a time. echo & q: The STR REPLACE cannot REPLACE multiple characters.
I REPLACE the first one with STR REPLACE.
Echo "$ uri/view/". trim (str_replace ('% 0a', '', rawurlencode(?line=}.'.html
Replace % 0A with NULL. the replacement is normal. now I need to replace multiple
The code is as follows:
Echo "$ uri/view/". trim (str_replace (array ("% 0A", ''), array (" % 0D ",''), rawurlencode(?line={.'.html
% 0A is replaced with null, but % 0D is replaced with null.
How can I replace this code with two characters at the same time?
------ Solution --------------------
Echo "$ uri/view/". trim (str_replace (array ("% 0A", "% 0D"), "", rawurlencode({line}}.'.html
------ Solution --------------------
Str_replace (array ("% 0A", ''), array (" % 0D ",''), rawurlencode ($ line ))
=>
Strtr (rawurlencode ($ line), array ("% 0A" => ''," % 0D "=> ''))