How to use scanf () to read a string with spaces in C language?

Landlord

Comment posted: 2011-01-14 15:39:55

#include <stdio.h>

int main (void)
{
int i;
Char a[5];

scanf ("%s", a);
printf ("%s\n", a);

return 0;

}

Run input Hello World
Enter
Then the output is only the part before the space, how to put the space after the part also output it?

2 floor

Reply at: 2011-01-14 17:27:23

Who says scanf can't do it?

#include <stdio.h>
int main ()
{
Char str[128];
scanf ("%[^\n]", str);
printf ("%s\n", str);
return 0;
}

Regular Expressions in scanf

int i;
//scanf ("%d%[abc]%s", &i, str, str2);
//printf ("%d%s%s\n", I,STR,STR2);
//scanf ("%[a-za-z0-9]", str);
//scanf ("%[^ABCE]", str);
scanf ("%[^a-z]", str);
printf ("%s\n", str);

2. Read in an address and display the contents of the memory address
int main (void)
{
Char ch= ' C ';
printf ("%p\n", &ch); Print the address of Ch.
Char *p;
cout<< "Enter an address:";
scanf ("%p", &p); Input the address displayed above
printf ("Value at location%p is%c\n", p,*p);
return 0;
}

3. Discard unwanted whitespace characters: scanf ("%c%c");

4. A non-whitespace character in the control string: Causes scanf () to read in and discard a matching character in the input stream. "%d,%d";

5. Compression Input: Add * to the format code before the user can tell scanf () to read the field, but not assign it to any variables.
scanf ("%c%*c, &ch); Use this method to eat the extra carriage return while the character is being processed.

Example 1: Extracting Tom from <sip:[email protected]>
Const char* URL = "<sip:[email protected]>";
Char uri[10] = {0};
sscanf (URL, "%*[^:]:%[^@]", URI);
cout << URIs << Endl;

Example 2: Extracting 12DDWDFF from Iios/[email protected]
Const char* s = "iios/[email protected]";
Char buf[20];
SSCANF (S, "%*[^/]/%[^@]", buf);
cout << buf << Endl;

3 floor

Reply at: 2011-01-14 21:15:47

int t[999];
int sum=0;
while (scanf ("%c", &t[sum++])!=eof);

How to use scanf () to read a string with spaces in C language?