I am completely confused with the self-written C code, and it is difficult to explain the strange behavior he

When I was reviewing the soft exam, I was going to extend it and thoroughly split the array name and pointer.

As a result, the code I wrote completely fainted myself...

Code:

1. # Include "stdio. H"
2. Int fun1 (int *)
3. {
5. Int * P = (int *) (& A + 1 );
6. Printf ("% d/N", * );
7. Printf ("% d/N", );
8. Printf ("% d/N", & );
9. Printf ("% d/N", & A + 1 );
10. Printf ("% d/N", P [-1]);
11. Return 0;
12. }
13. Int fun2 (INT **)
14. {
15. Int * P = (int *) (a + 1 );
16. Printf ("% d/N", ** );
17. Printf ("% d/N", * );
18. Printf ("% d/N", );
19. Printf ("% d/N", A + 1 );
20. Printf ("% d/N", P [-1]);
21. Return 0;
22. }
23. Int fun3 (int *)
24. {
26. Int * P = (int *) (INT (*) [5]) (a) + 1 );
27. Printf ("% d/N", * );
28. Printf ("% d/N", );
29. Printf ("% d/N", & );
30. Printf ("% d/N", & A + 1 );
31. Printf ("% d/N", P [-1]);
32. Return 0;
33. }
35. Int main ()
36. {
37. Int A [5] = {1, 2, 3, 4, 5 };
38. Int * P = (int *) (& A + 1 );
39. Printf ("% d/N", * );
40. Printf ("% d/N", );
41. Printf ("% d/N", & );
42. Printf ("% d/N", & A + 1 );
43. Printf ("% d/N", P [-1]);
44. Fun1 ();
45. Fun3 ();
46. Fun3 ();
47. Fun2 (& );
48. Return 0;
49. }

The output of two fun3 (a) is different...

And fun2 should not output 5 at all.

And if the function is executed in this Order

Fun1 ();
Fun2 (& );
Fun3 ();

Fun3 does not work !!! Khan... can you help me?