principle:
1. Change the expression of the middle order to an expression
2. The current character is a number, put that number in the stack
3. The current character is an operator, take out two trees from the stack, operate from the operator, and put the results of the operation into the stack
4. Repeat until the character is finished. Only one element is left in the stack, that is, the result of the operation
PS: I did not deal with it. Only be able to perform operations within 10, assuming there is a need to expand
Package Com.lip.datastructure.tree;import Java.util.iterator;import Java.util.stack;public class Calculator{public static void Main (string[] args) {String obj = "A * (b+c) +c/d"; String obj1 = "1+3 +9/3"; System.out.println (obj1+ "=" +calculator (obj1));} Use post-order expressions to calculate the///principle: 1. When the period character is a letter or a number, it is directly into the stack//2. The current character is an operator that takes out two numbers from the stack//3. Put the results of the calculation into the stack, the last remaining element of the stack is the result public static T Calculator (String obj) {string postobj=tranform (obj); System.out.println (); Stack<integer>stack=new stack<integer> (); for (int i=0;i<postobj.length (); i++) {char ch= Postobj.charat (i); if (Character.isletterordigit (CH))//character or number {Stack.push (Integer.parseint (ch+ ""));} else//operator {//Remove two number int op1,op2;op1=stack.pop (); Op2=stack.pop (); switch (CH) {case ' + ': Stack.push (OP2+OP1); Break;case ' -': Stack.push (OP2-OP1); Break;case ' * ': Stack.push (OP2*OP1); Break;case '/': Stack.push (OP2/OP1); break;default:break ;}}} return Stack.pop ();} The middle sequence traversal is changed to perhaps traverse public static string Tranform (String obj) {stack<character> Stack = new Stack<characteR> (); String obj2 = ""; for (int i = 0; I < obj.length (); i++) {Char ch = obj.charat (i), if (Character.isletterordigit (CH))//letter or digital Direct output {obj2 + = ch; System.out.print (CH);} else if (ch = = ') ') operations characters stop out of stack {char temp;while (temp = Stack.pop ())! = ' (') {obj2 + = temp; System.out.print (temp);}} else//Precedence of the comparison operator {if (Stack.isempty ()) {Stack.push (ch); continue;} Char temp = Stack.peek (), while (ICP (CH) <= ISP (temp))//stack priority is less than the priority in the stack, the stack {System.out.print (temp); Obj2 + = temp; Stack.pop (); if (Stack.isempty ()) break;temp = Stack.peek ();} Stack.push (ch);}} Bounce the remaining elements out of the stack while (!stack.isempty ()) {Char temp = Stack.pop (); Obj2 + = temp; System.out.print (temp);} return obj2;} Operator precedence within stack private static int ISP (char ch) {switch (ch) {case ' + ': Case '-': return 2;case ' * ': Case '/': Return 4;case ') ': RE Turn 7;case ' (': Return 1;default:break;} return 0;} Precedence priority of the operator into the stack private static int ICP (char ch) {switch (ch) {case ' + ': Case '-': return 3;case ' * ': Case '/': Return 5;case ') ': Return 1;case ' (': return 7;default:break;}return 0;}}
Implementation of the calculator data structure (JAVA) (iv)