Implemented in C: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value.

Source: Internet
Author: User
Tags pow

To get this topic, we will first think of using loops to complete.

But not every operator is a "+" sign.

Therefore, we are here to use (-1) of the I-side to do "+" "-" number control.

The loop variable i is then treated as the denominator.

Here we have the idea of the loop body is basically OK.

It is important to note that the calculation results here are expressed in decimals, so it is not possible to define variables with int integers.

The code is as follows:

#include <stdio.h>#include<math.h>intMain () {inti; floatsum=0.0, temp=0.0;  for(i =1; I <= -; i++) {Temp= POW (-1, i +1); Sum= Sum + temp *1/i; } printf ("sum is%f\n", sum); System ("Pause"); return 0;}

A function pow is used in the code,

This function is used to represent the function of the secondary side, so it is necessary to refer to the header file MATH.H.

Of course, we do not use the POW function to complete the programming.

In the loop body, we can define an auxiliary variable flag to make flag=1.

In the loop body, we just need to make flag=-flag at the end,

This allows the flag to be transformed between 1 and 1 to complete programming.

The code is as follows:

#include <stdio.h>intMain () {intI, flag =1; floatsum =0.0;  for(i =1; I <= -; i++) {sum= Sum + flag* (1.0/i); Flag= -Flag; } printf ("sum is%f\n", sum); System ("Pause"); return 0;}

Finally, attach the result of the program running:

Implemented in C: Calculate 1/1-1/2+1/3-1/4+1/5 ... + 1/99-1/100 value.

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