Introduction to C programming--a comprehensive exercise (iv) on-machine test questions

This procedure is our College C language on the machine test questions, by my classmates summed up, and shared to everyone. (Word of the program, layout some problems, please forgive me)

Sum or product of n (item) data

The and (or product) of n data is #include <stdio.h>int main () {     int a[100];    int i   = 0;     int n;     printf ("This program will implement tired and there are cumulative features, please enter the number of items \ n");     scanf ("%d", &n);     printf ("Please input each \ n");     for (i   = 0; i<n; i++) {         scanf ("%d", &a[i]);      }    Beg tired and     int sum = 0;     for (i   = 0; i<n; i++) {         sum = sum + a[i];      }     printf ("sum =%d\n", sum);    Seek cumulative     int ji = 1;     for (i   = 0; i<n; i++) {         ji  = Ji * a[i];      }     printf ("Ji  =%d\n", Ji);      return 0;  }

the sum or product of the numbers of decimal integers

1#include <stdio.h>

2

3int Main ()

4 {

5 int A;

6 int sum;

7 int ji;

8 int b[10];

9 scanf ("%d", &a);

Ten if (a<10) {

printf ("Sum =%d\n", a);

printf ("Ji =%d\n", a);

13}

+ Else if (a>=10&&a<100) {

B[0] = A/10;

B[1] = a% 10;

printf ("sum =%d\n", b[0]+b[1]);

printf ("Ji =%d\n", b[0]*b[1]);

19}

ElseIf (a>=100&&a<1000) {

B[0] = a/100;

B[1] = (a% 100)/10;

B[2] = ((a% 100)% 10)/1;

printf ("sum =%d\n", b[0]+b[1]+b[2]);

printf ("Ji =%d\n", b[0]*b[1]*b[2]);

26}

The else if (a>=1000&&a<10000) {

B[0] = a/1000;

B[1] = (a% 1000)/100;

B[2] = ((a% 1000)% 100)/10;

B[3] = (((a% 1000)% 100)%10)/1;

printf ("sum =%d\n", b[0]+b[1]+b[2]+b[3]);

printf ("sum =%d\n", b[0]*b[1]*b[2]*b[3]);

34}

+ Else

printf ("It is too big\n");

37

38

0;

40}

Ask average of n data (exact value or rounding with fractional parts)

1#include <stdio.h>

2

3int Main ()

4 {

5 int n;

6 int i = 0;

7 int sum = 0;

8 int a[100];

9 float average;

Ten scanf ("%d", &n);

printf ("\ n");

(i = 0; i< N; i++) {

scanf ("%d", &a[i]);

14}

15

(i = 0; i< N; i++) {

sum = sum + a[i];

18}

printf ("average =%.3f\n", (float) sum/n);

return 0;

21}

To find the maximum (or minimum) value

1#include <stdio.h>

2

3int Main ()

4 {

5 int n;

6 int a[100];

7 int i = 0;

8 int Max;

9 int Min;

Ten scanf ("%d", &n);

if (n> 100) {

printf ("N is too big\n");

13}

else{

for (i = 0; i < n; i++) {

scanf ("%d", &a[i]);

17}

Max = a[0];

for (i = 1; i<n; i++) {

if (Max<a[i])

Max = A[i];

22}

Min = a[0];

(i = 1; i<n; i++) {

if (Min>a[i])

Min = A[i];

27}

28

29

30

printf ("max =%d\n", max);

printf ("min =%d\n", min);

33

34}

return 0;

36}

liters (Descending) Order sequencing

1#include <stdio.h>

2

3int Main ()

4 {

5 int a[100], I, J, temp, R;

6 int n;

7 scanf ("%d", &n);

8 if (n>100) {

9 printf ("N is Toobig");

10}

else{

(i = 0; i< N; i++) {

scanf ("%d", &a[i]);

14}

(i = 0; i<n-1; i++) {

R = i;

+ for (j = i+ 1; j<n; J + +) {

if (a[r]> a[j])

R = J;

20}

21st

if (r! = i) {

temp = A[i];

A[i] = A[r];

A[R] = temp;

26}

27}

28

(i = 0; i< N; i++)

printf ("%d", a[i]);

31}

32

33

return 0;

35}

Letter Case Conversion

1#include <stdio.h>

2#include <string.h>

3

4int Main ()

5 {

6 Char a[100];

7 int i;

8 scanf ("%s", a);

9 printf ("beforeexchange\n\t%s\n", a);

Ten for (i = 0; I<strlen (a); i++) {

if (a[i]>=97&&a[i]<=122)

A[i] = a[i]-32;

All else if (a[i]>=65&&a[i]<=90)

A[i] = A[i] + 32;

15}

printf ("After exchange\n\t%s\n", a);

0;

18}

Count the number of occurrences of a character in a string

1#include <stdio.h>

2#include <string.h>

3

4int Main ()

5 {

6 Char a[100];

7 Char B;

8 int n = 0;

9 int i;

Ten scanf ("%s\n", a);

One scanf ("%c", &b);

12

13

+ for (i = 0; I<strlen (a); i++) {

if (a[i] = = b)

n++;

17}

18

printf ("%d\n", N);

return 0;

21}

Connect two strings

1#include <stdio.h>

2#include <string.h>

3

4int Main ()

5 {

6 Char a[100], b[100];

7 memset (A, 100, 0);

8 memset (b, 100, 0);

9

Ten int i = 0;

one int n;

int m;

scanf ("%s", a);

scanf ("%s", b);

15

n = strlen (a);

+ M = strlen (b);

18

for (i= 0; i<m; i++) {

A[n+i]=b[i];

21}

A[m+n] = ' + ';

23

printf ("%s\n", a);

return 0;

26}

copies the substring before (or after) the specified character the previous;

1#include <stdio.h>

2

3//defines a function such as

4int Fu_zhi (Char *str1, char *str2, Char ch)

5 {

6 int i = 0, j = 0;

7 int k;

8 while (STR1[I]!=CH)

9 i++;

10

One j = i;

K = i;

while (i>=0) {

STR2[J-1] = str1[i-1];

i--;

j--;

17}

Str2[k] = ' + ';

return 0;

20}

21st

23int Main ()

24 {

Char a[100];

+ Char b[100];

Char ch;

printf ("Please enter the specified character:");

scanf ("%c", &ch);

printf ("Please enter the specified string:");

scanf ("%s", a);

Fu_zhi (A, b, ch);

printf ("%s\n", b);

37

return 0;

39}

After that;

1#include <stdio.h>

2

3//defines a function such as

4int Fu_zhi (Char *str1, char *str2, Char ch)

5 {

6 int i = 0, j = 0;

7 while (STR1[I]!=CH)

8 i++;

9 while (str1[i]!= ') {

Ten str2[j]= str1[i+1];

One by one i++;

j + +;

13}

STR2[J] = ' + ';

return 0;

16}

17

18

19int Main ()

20 {

(+ char a[100];

-Char b[100];

-Char ch;

24

printf ("Please enter the specified character:");

scanf ("%c", &ch);

printf ("Please enter the specified string:");

scanf ("%s", a);

29

Fu_zhi (A, b, ch);

31

printf ("%s\n", b);

33

return 0;

35}

the input and output of a struct type variable (or array element) value

1#include <stdio.h>

2#include <stdlib.h>

3

4struct zhengjiewei{

5 Char a[20];

6 int b;

7 int c[10][10];

8 Char ch;

9

10};

11

12int Main ()

13 {

Zhengjiewei-struct * TWOB;

Twob = (struct Zhengjiewei *) malloc (sizeof (struct zhengjiewei));

16//To assign memory to a variable in a struct, you cannot treat it as a local variable ...

scanf ("%s", twob->a);

scanf ("%d", &twob->c[3][6]);

printf ("%d\n", twob->c[3][6]);

printf ("%s\n", twob->a);

21st

return 0;

23

24}

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Introduction to C programming--a comprehensive exercise (iv) on-machine test questions