Is that OK? How to solve it

Is that OK?
All the letters of the string and 0 are identical? Ask for explanations

PHP Code

  
   if ("e" = = 0) {    echo "Yes";} #result: #Yes

------Solution--------------------
"E" is not a variable in memory, nothing ....
------Solution--------------------
This by:

PHP code

echo "e" = = = 0; 
 ------Solution--------------------
 PHP will automatically convert the type of the variable, and the int and string comparisons will then convert the string to int so that all the strings are 0, then the result is OK, you can use = = = Congruent to determine 
------solution--------------------
 To resolve more clearly: 
 
 Echo intval (' e '); #转换不成功, default 0 (print:0) 
 Echo intval (' 1ds2e '); #字符串中有整数出现, take the first occurrence of the position, convert to int (print:1) 
 
 
    
     discussion  
    
 
    
 this way:php c
   Ode 
    
 echo "e" = = = 0; 
    
 
    
------Solution--------------------
 
 This is wrong, "there are integers in the string, then take the first occurrence and convert to int (print:1)" 
 
   The 
 should look like this: 
 
 An integer appears in the string, and the integer at the beginning of the string is taken out, converted to an int 
 
 
    
     discussion  
    
 
    
 To resolve this more clearly: 
   
    
 
    
 Echo intval (' e '); #转换不成功, default 0 (print:0) 
    
 Echo intval (' 1ds2e '), #字符串中有整数出现, take first occurrence, convert to int (print:1)
   
    
 
    
 Reference: 
    
 
    
 This way:php code 
    
 echo "e" = = = 0; 
    
 
    
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