Java double precision multiplication, resulting in incorrect resolution __java

Source: Internet
Author: User
The public static void main (string[] args) {
		//double is computed as a dual
		x = 4.85;
		Double y = 6600.00;
		Double z = x * y;
		System.out.println (z);//32009.999999999996
		
		BigDecimal a = bigdecimal.valueof (x);
		BigDecimal B = bigdecimal.valueof (y);
		BigDecimal C = a.multiply (b);
		System.out.println (c);//32010.00
	}
Floating-point values in Java are represented by binary systems, and in binary systems it is impossible to represent a number like 1/10, and it is impossible to express 1/3 accurately in decimal. If there is no error in the calculation, the Java.math.BigDecimal class is used, which can realize the floating-point arithmetic with arbitrary precision.
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