JAVA Compute Time Difference

For example: it's 2004-03-26 13:31:40
Last was: 2004-01-02 11:30:24
I now want to get two date difference, the form of difference is: xx days xx hours xx minutes xx seconds
Method One:

1DateFormat DF =NewSimpleDateFormat ("Yyyy-mm-dd HH:mm:ss"); 2 Try  3 {   4Date D1 = Df.parse ("2004-03-26 13:31:40"); 5Date D2 = Df.parse ("2004-01-02 11:30:24"); 6     Longdiff = d1.gettime ()-D2.gettime (); 7     LongDays = diff/(1000 * 60 * 60 * 24); 8 }   9 Catch(Exception e)Ten {    One}

Method Two:

1SimpleDateFormat DF =NewSimpleDateFormat ("Yyyy-mm-dd HH:mm:ss"); 2Java.util.Date now = Df.parse ("2004-03-26 13:31:40"); 3Java.util.Date date=df.parse ("2004-01-02 11:30:24"); 4    LongL=now.gettime ()-Date.gettime (); 5    Longday=l/(24*60*60*1000); 6    LongHour= (l/(60*60*1000)-day*24); 7    LongMin= ((l/(60*1000))-day*24*60-hour*60); 8    LongS= (l/1000-day*24*60*60-hour*60*60-min*60); 9System.out.println ("+day+" Days "+hour+" hours "+min+" minutes "+s+" seconds ");

Method Three:

1SimpleDateFormat DFS =NewSimpleDateFormat ("Yyyy-mm-dd HH:mm:ss"); 2Java.util.Date begin=dfs.parse ("2004-01-02 11:30:24"); 3Java.util.Date end = Dfs.parse ("2004-03-26 13:31:40"); 4    LongBetween= (End.gettime ()-begin.gettime ())/1000;//divided by 1000 to convert into seconds .5    Longday1=between/(24*3600); 6    Longhour1=between% (24*3600)/3600; 7    LongMinute1=between%3600/60; 8    LongSecond1=between%60/60; 9System.out.println ("+day1+" Days "+hour1+" hours "+minute1+" minutes "+second1+" seconds ");

Compare time:

1String s1= "2008-01-25 09:12:09"; 2String s2= "2008-01-29 09:12:11"; 3Java.text.DateFormat df=NewJava.text.SimpleDateFormat ("Yyyy-mm-dd HH:mm:ss"); 4Java.util.Calendar c1=java.util.Calendar.getInstance (); 5Java.util.Calendar c2=java.util.Calendar.getInstance (); 6 Try  7 {   8 C1.settime (Df.parse (S1)); 9 c2.settime (df.parse (S2)); Ten}Catch(java.text.ParseException e) { OneSYSTEM.ERR.PRINTLN ("Not formatted correctly");  A }    - intresult=C1.compareto (C2);  - if(result==0)    theSYSTEM.OUT.PRINTLN ("C1 equal C2");  - Else if(result<0)    -SYSTEM.OUT.PRINTLN ("C1 Less than C2");  - Else   +SYSTEM.OUT.PRINTLN ("C1 greater than C2");

JAVA Compute Time Difference