Java Get user public network IP and location

Most of the code on the Internet is outdated, so get ready to do it yourself. Get the data source

Http://ip.chinaz.com/getip.aspx

The effect is as follows:

The code is as follows:

public static string Getmyip () throws IOException {  
		 	string url= "http://ip.chinaz.com/getip.aspx";
		 	InputStream is = new URL (URL). OpenStream ();
		    try {
		      BufferedReader rd = new BufferedReader (new InputStreamReader (IS, Charset.forname ("UTF-8"));
		      
		      StringBuilder sb = new StringBuilder ();
		      int CP;
		      while (cp = Rd.read ())!=-1) {
		        sb.append ((char) CP);
		      String Jsontext =  sb.tostring ();;
		      Jsontext=jsontext.replaceall ("'", "");
		      Jsontext=jsontext.substring (1,jsontext.length ()-1);
		      Jsontext=jsontext.replaceall (",", "<br/>");
		      return jsontext;
		    } finally {
		      is.close ();
		     System.out.println ("At the same time it can be seen from here that even if return, will still implement finally." ");
		    }