Java gets the day after the current date __java

Given a date, how do I get the day after this date? This is not a simple current date plus one thing. On the last day of the year, the last day of the month will be transferred to the next one months, which will make a mistake. Here is a simple way to use the method provided by the Calendar class. Words are not more directly on the code.

public static string Getthenextdate (String date) {//201711191600 if (date!=null&&date.lengt
		H () >=8) {date=date.substring (0, 8);
		}else {return "";
		} String year=date.substring (0,4);
		String month=date.substring (4,6);
		String day1=date.substring (6,8);
		System.out.println (year+ "" +month+ "" +day1);
		String datestr=year+ "-" +month+ "-" +day1;
		Date Mydate=null;
		Calendar calendar=calendar.getinstance ();
		try {mydate=new SimpleDateFormat ("Yyyy-mm-dd"). Parse (DATESTR);
		catch (ParseException e) {e.printstacktrace ();
		} calendar.settime (MyDate);
		int Day=calendar.get (calendar.date);
		Calendar.set (Calendar.date, day+1);
		String dayafter=new SimpleDateFormat ("Yyyy-mm-dd"). Format (Calendar.gettime ());
		System.out.println (Dayafter);
		String [] Datearray=dayafter.split ("-");
		String dayafter1= "";
		for (int i = 0; i < datearray.length i++) {dayafter1+=datearray[i];
	return dayAfter1; }

The landlord test, copy can be used.