Title Description:
Given strings s and t, determine if they are isomorphic.
The strings is isomorphic if the characters in s can is replaced to get t.
All occurrences of a character must is replaced with another character while preserving the order of characters. No, characters may map to the same character and a character may map to itself.
For example,
Given "egg"
, "add"
return True.
Given "foo"
, "bar"
return FALSE.
Given "paper"
, "title"
return True.
Problem Solving Ideas:
Mapping with arrays. Note that each time the dictionary map is assigned a value of i+1, this is to prevent confusion with the assignment at the time of the first mapping. (because the initialization of the array is assigned a value of 0, if each assignment is I, then the first assignment is also 0, so it is confusing).
The code is as follows:
public class Solution {public Boolean isisomorphic (string s, String t) { int[] MapS = new int[128]; int[] mapt = new int[128]; for (int i = 0; i < s.length (); i++) { if (Maps[s.charat (i)] = Mapt[t.charat (i)]) return false; Maps[s.charat (i)] = Mapt[t.charat (i)] = i + 1; } return true; }}
Java [Leetcode 205]isomorphic Strings