Java rounding to keep decimal number implementation method _java

Source: Internet
Author: User

Mode one:

Double F = 3.1516;
BigDecimal B = new BigDecimal (f);
Double f1 = B.setscale (2, bigdecimal.round_half_up). Doublevalue ();

Mode two:

New Java.text.DecimalFormat ("#.00"). Format (3.1415926);
#.00 represents a two-bit decimal #.0000 four-bit decimal, and so on ...

Mode three:

Double d = 3.1415926;
String result = String.Format ("%.2f", D);
%.2f%. Represents a floating-point type with a result of an arbitrary number of digits before the decimal point of 2 representing a two-bit decimal format.

Method Four:

Math.Round (5.2644555 *) * 0.01D;
String.Format ("%0" + + "D", 23) 23 less than 15 is on the front complement 0

The above is a small series for everyone to bring the Java rounding to keep the decimal points to achieve the full content of the method, I hope to help you, a lot of support cloud Habitat Community ~

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