Java's scanner

Reference Http://how2j.cn/k/operator/operator-scanner/658.html#nowhere

Need to input data from the console, so you need to use the scanner class

Reading integers using scanner

import Java.util.Scanner; Public classHelloWorld { Public Static voidMain (string[] args) {Scanner s=NewScanner (System.inch); intA =S.nextint (); System. out. println ("First integer:"+a); intb =S.nextint (); System. out. println ("a second integer:"+b); }}

Execute the program

Using scanner to read floating-point numbers

import Java.util.Scanner;    Public class HelloWorld {    publicstaticvoid  main (string[] args) {        new Scanner (System.  in);         float a = s.nextfloat ();        System. out. println (" read the value of the floating-point number is:"+a);}     }

Execute the program

Reading a string using scanner

import Java.util.Scanner;    Public class HelloWorld {    publicstaticvoid  main (string[] args) {        new Scanner (System.  in);         = s.nextline ();        System. out. println (" the string read is:"+a);}    }

After the integer is read, the string is then read

Note that if you read the integer through Nextint () and then read the string, the return line is read: "\ r \ n" because Nextint only reads the digital information, but does not read the carriage return line "\ r \ n".

Therefore, if you need to read the integer in the business, then read the string, then you should execute two times nextline (), the first time is to take a carriage return line, the second time is to read the real string

import Java.util.Scanner;  Public classHelloWorld { Public Static voidMain (string[] args) {Scanner s=NewScanner (System.inch); inti =S.nextint (); System. out. println ("The integer read is"+i); String RN=S.nextline (); String a=S.nextline (); System. out. println ("the string to read is:"+a); }}

Java's scanner