Javascript-how to use the ajaxpost complex json data

{Code...} newbie, please ask why this always displays error, that is, post fails? How to change it? How can I use PHP to parse the data received in the background?

$ (Function () {$. ajax ({url: 'Check. php ', // api address data: {"head": {"name": "test",}, "body": {"age ": "2" ,}}, type: 'post', // data transmission method dataType: 'json', // data Transmission Format cache: false, success: function (data) {// callback function after successful execution. data is the returned data alert (data) ;}, error: function () {alert ('error ');}});});

Newbie, please ask why this always displays error, that is, post fails? How to change it? How can I use PHP to parse the data received in the background?

Reply content:

$ (Function () {$. ajax ({url: 'Check. php ', // api address data: {"head": {"name": "test",}, "body": {"age ": "2" ,}}, type: 'post', // data transmission method dataType: 'json', // data Transmission Format cache: false, success: function (data) {// callback function after successful execution. data is the returned data alert (data) ;}, error: function () {alert ('error ');}});});

Newbie, please ask why this always displays error, that is, post fails? How to change it? How can I use PHP to parse the data received in the background?

Encode Json as a string, send it to the background with a parameter, and decode it in the background to parse json;

Var json = {"head": {"name": "test",}, "body": {"age": "2" ,}}; var str = JSON. stringify (json); $ (function () {$. ajax ({url: 'Check. php ', // api address data: {json: escape (str)}, type: 'post', // data transmission method dataType: 'json ', // data Transmission Format: cache: false, success: function (data) {// The callback function after successful execution. data is the returned data alert (data) ;}, error: function () {alert ('error ');}});});

In this way, the complex Json object is passed as a parameter to the background.
Received by the php Background: The value of POST ["json"] is decoded and parsed;

Json format error. comma is not required after "test" and "2 ".

Json encode is converted to a string, and json_decode on the php side is enough, for example
Data: {values: $. jsonEncode ({header:...})} // I forgot how to use jsonencode on the js end. check it myself.
Then
$ Parameters = json_decode ($ _ POST ['values']);

PHP is used for background reception:json_decode(file_get_contents('php://input'), true);

First, errror indicates that your server does not return data in JSON format,
Then, "head", "body" should be followed by a string,
Finally, on the PHP side, You Can $ _ POST ['head'], $ _ POST ['body'] to obtain the head and body strings.

ageIs there a space behind it? RemembertypeIt should bePOSTAnddataTypeAre you sure you have any questions?

$ (Function () {$. ajax ({url: 'Check. php ', // api address data: {"head": {"name": "test",}, "body": {"age ": "2" ,}}, type: 'post', // data transmission method dataType: 'application/json', // Data Transmission Format cache: false, success: function (data) {// The callback function after successful execution. data is the returned data alert (data) ;}, error: function () {alert ('error ');}});});

The format is incorrect. Remove the commas (,) after 'test' and '2'. Try again.