[Leetcode] 65. Valid number Java

Source: Internet
Author: User

Topic:

Validate if a given string is numeric.

Some Examples:
"0"=true
" 0.1 "=true
"abc"=false
"1 a"=false
"2e10"=true

Note:it is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.

Update (2015-02-10):
The signature of the C++ function had been updated. If you still see your function signature accepts a const char * argument, please click on the reload button to reset your code Definition.

test instructions and analysis: determines whether a string can be converted to a legitimate The number , the main note that at most only one decimal point and e,e cannot have the decimal point first or the last digit can be a decimal point, +/-can only appear in the first bit or after the first bit of E.

Code:

class Solution {public Boolean isnumber (string s) {//Determine if a string is a valid number        s = S.trim ();        Boolean pointseen = false;        Boolean eseen = false;        Boolean isnumber = false;            for (int i=0;i<s.length (); i++) {Char temp = S.charat (i);            if (temp>= ' 0 ' && temp<= ' 9 ') {Isnumber = true; }else if (temp = = '. ')                {if (Eseen | | pointseen) return FALSE;            Pointseen = true;                }else if (temp = = ' E ') {if (Eseen | |!isnumber) return FALSE;                Eseen = true;            Isnumber = false;                    }else if (temp = = ' + ' | | temp== '-') {//can only be in the first or isnumber followed by +/-if (i!=0 && s.charat (i-1)! = ' E ')                return false;            Isnumber = false;        }else return false;    } return isnumber; }}

  

[Leetcode] 65. Valid number Java

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