Leetcode Keyboard Row500 Java

1  Public classSolution {2      Publicstring[] Findwords (string[] words) {3List<string> onerowwords =NewArraylist<string>();4String[] Keyboard = {"Qwertyuiop", "ASDFGHJKL", "ZXCVBNM"};5          for(String word:words) {6String Realword =Word;7Word = Word.tolowercase ();//each letter becomes lowercase8             Char[] Strbit =Word.tochararray ();9             intCount = 0;Ten              for(Charch:strbit) { One                 if(Keyboard[0].indexof (strbit[0])! =-1) {//first letter in row one A                     if(Keyboard[0].indexof (ch) = =-1) {//Other letters must also be skipped in the first row otherwise -                          Break; -                     } the}Else if(Keyboard[1].indexof (strbit[0])! =-1) {//The first letter is in the second row . -                     if(Keyboard[1].indexof (ch) = =-1) { -                          Break; -                     } +}Else if(Keyboard[2].indexof (strbit[0])! =-1) {//first letter in row three -                     if(Keyboard[2].indexof (ch) = =-1) { +                          Break; A                     } at                 } -Count + +; -             } -             if(Count = =strbit.length) { - Onerowwords.add (Realword); -             } in         } -string[] Onerowwordsarray =Newstring[onerowwords.size ()]; to          for(inti=0; I<onerowwords.size (); i++){ +Onerowwordsarray[i] =Onerowwords.get (i); -         } the          *         returnOnerowwordsarray; $     }Panax Notoginseng}

Leetcode Keyboard Row500 Java