Leetcode-Path Sum
Path Sum Total Accepted: 31405 Total Submissions: 104326My SubmissionsQuestionSolution
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and
sum = 22
,
5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1
Return true, as there exist a root-to-leaf path5->4->11->2
Which sum is 22.
Show TagsHave you met this question in a real interview? Yes No
Discuss
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: int flag=0; bool hasPathSum(TreeNode *root, int sum) { if(root==NULL) return false; pathSum(root,0,sum); if(flag==1) return true; else return false; } int pathSum(TreeNode *root,int res,int sum) { if(root==NULL) return 0; res+=root->val; int l=pathSum(root->left,res,sum); int r=pathSum(root->right,res,sum); if((l+r)==0&&res==sum) { flag=1; } }};