#-*-encoding=utf-8-*-import operator #按字典值排序 (default ascending) x = {1:2, 3:4, 4:3, 2:1, 0:0} sorted_x = sorted (X.iteritems () , Key=operator.itemgetter (1)) Print sorted_x #[(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)] #如果要降序排序, you can specify Reverse=true sorte d_x = sorted (X.iteritems (), Key=operator.itemgetter (1), reverse=true) print sorted_x #[(3, 4), (4, 3), (1, 2), (2, 1), ( 0, 0)] #或者直接使用list的reverse方法将sorted_x顺序反转 #sorted_x. Reverse () #取代方法是, with lambda expression sorted_x = sorted (X.iteritems (), key =lambda x:x[1]) print sorted_x #[(0, 0), (2, 1), (1, 2), (4, 3), (3, 4)] sorted_x = sorted (X.iteritems (), Key=lambda X:X[1], reverse=true) print sorted_x #[(3, 4), (4, 3), (1, 2), (2, 1), (0, 0)]#包含字典dict的列表list的排序方法与dict的排序类似, as follows: x = [{' Name ': ' Homer ', ' age ': ' the ', ' {' name ': ' Bart ', ' Age ': ten}] sorted_x = sorted (x, Key=operator.itemgetter (' name ')) PRI NT sorted_x #[{' age ': Ten, ' name ': ' Bart '}, {' Age ': ", ' name ': ' Homer '}] sorted_x = sorted (x, Key=operator.itemgetter (' N Ame '), reverse=true) print sorted_x #[{' age ': ", ' name ': ' Homer '}, {' Age ': Ten, ' name ': ' Bart '}] sorted_x = sorted (x, K Ey=lambda x:x[' name ']) print sorted_x #[{' age ': Ten, ' name ': ' Bart '}, {' Age ':, ' name ': ' Homer '}] sorted_x = sorted ( X, Key=lambda x:x[' name '], reverse=true) print sorted_x #[{' age ': ", ' name ': ' Homer '}, {' Age ': Ten, ' name ': ' Bart '}]
List sort in Python, dictionary sort, dictionary sort in list