Map of the Java collection

Source: Internet
Author: User
Tags set set

1. Base and delete functions of map collection

1  Public classDemo1_map {2 3     /*4 * The Map collection is in the form of a key-value pair, and the underlying dependency is the set set5      * 6 * A. Adding features7 * v put (K key, v value)8 * If the key is deposited for the first time, the element is stored directly, returning null (in essence, it is the same as the key exists, only the null is overwritten)9 * If the key is not deposited for the first time, replace the previous value with the value and return the previous valuesTen * b. Remove Features One * void Clear () Removes all key-value information A * V Remove (Object key) removes the element value corresponding to the specified key and returns the value, returning NULL when the passed key value does not exist - * C. Judging function - * Boolean containskey (Object key) to determine if this key is included in the collection the * Boolean containsvalue (Object value) determines whether the collection contains the specified value - * Boolean isEmpty () determines whether the set is empty - * d. Get features - * set<map.entry<k,v>> entryset () + * V get (Object key) Gets the value according to the key - * set<k> KeySet () Gets the collection of all the keys in the collection + * collection<v> values () gets a collection of all the values in the collection and returns a Conllection A * E. Length function at * int size () returns the number of all key-value pairs in the collection -      *  -      */ -      Public Static voidMain (string[] args) { -  -         //demo1 (); in         //Demo2 (); -         //Demo3 (); tomap<string, integer> map =NewHashmap<>(); +Integer I1 = Map.put ("Zhang San", 23); -Integer i2 = Map.put ("John Doe", 24); theInteger i3 = Map.put ("Harry", 25); *Integer i4 = Map.put ("Zhao Liu", 26); $Integer i5 = map.put ("Zhang San", 26);Panax NotoginsengSet<entry<string, integer>> set =Map.entryset (); -SYSTEM.OUT.PRINTLN (set);//[John Doe = 24, Zhang San = 26, Harry = 25, Zhao Liu =26] theSystem.out.println (Map.values ());//[ +, +, +] +          A      } the  +     /** - * Judging function $      */ $      Public Static voidDemo3 () { -map<string, integer> map =NewHashmap<>(); -Map.put ("Lisi", 24); the         BooleanB1 = Map.containskey ("Lisi");  -System.out.println (B1);//trueWuyi         BooleanB2 = Map.containsvalue (24) ;  theSystem.out.println (B2);//true -     } Wu  -     /** About * Delete function $      */ -      Public Static voidDemo2 () { -map<string, integer> map =NewHashmap<>(); -Map.put ("John Doe", 24); AInteger i = Map.Remove ("Zhang San");  +System.out.println (i);//NULL theInteger I1 = Map.Remove ("John Doe"); -System.out.println (I1);// - $     } the  the     /** the * Add features the      */ -      Public Static voiddemo1 () { inmap<string, integer> map =NewHashmap<>(); theInteger I1 = Map.put ("Zhang San", 23); theInteger i2 = Map.put ("John Doe", 24); AboutInteger i3 = Map.put ("Harry", 25); theInteger i4 = Map.put ("Zhao Liu", 26); theInteger i5 = map.put ("Zhang San", 26); the System.out.println (map); + System.out.println (i1); - System.out.println (i2); the System.out.println (i3);Bayi System.out.println (I4); the System.out.println (i5); the     } -  -}

2. Traverse the Map Collection

1  Public classDemo2_map {2 3     /**4      * @paramargs5 * Traverse Map Collection6      * 7      */8      Public Static voidMain (string[] args) {9 Tenmap<string, integer> map =NewHashmap<>(); OneMap.put ("Zhang San", 23); AMap.put ("John Doe", 24); -Map.put ("Harry", 25); -Map.put ("Zhao Liu", 26); the          -         /* - Iterating through the map collection using iterators - set<string> Set = Map.keyset (); + iterator<string> it = Set.iterator (); - While (It.hasnext ()) { + String key = It.next (); A System.out.println (key + "=" + map.get (key)); at         }*/ -          -          -         //traversing the map collection with an enhanced for loop -          for(String string:map.keySet ()) { -System.out.println (string + "=" +Map.get (String)); in         } -     } to  +}

Map of the Java collection

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.