P1903 [TEMPLATE] multipart/with modification of Moq (number color), p1903

P1903 [TEMPLATE] multipart/with modification of Moq (number color), p1903
Description

Mo mo purchased a set of N color brushes (some of which may have the same color) and placed them in a row. You need to answer Mo's questions. Mo mo will issue the following command as you do:

1. q l r indicates asking you how many different colors there are from the L paint brush to the R paint brush.

2. r p Col replaces the P paint brush with the color Col.

Do you know what you need to do to meet Momo's requirements?

Input/Output Format

Input Format:

 

Two integers (N and M) in the row 1st represent the number of the initial paint brushes and the number of tasks that ink and ink will do.

N integers in row 2nd, representing the I-th paint brush color in the first paint brush row, respectively.

Lines from 3rd to 2nd + M represent one thing that Mo mo will do. For details about the format, refer to cadre points.

 

Output Format:

 

For each Query, you need to give a number in the corresponding row, representing the number of different colors from the L paint brush to the R paint brush.

 

Input and Output sample input sample #1:

6 51 2 3 4 5 5Q 1 4Q 2 6R 1 2Q 1 4Q 2 6

Output sample #1:

4434

Description

For 100% of data, N ≤ 10000, M ≤ 10000, the modification operation is no more than 1000 times. All integers in all input data are greater than or equal to 1 and cannot exceed 10 ^ 6.

Source: bzoj2120

The data in this question is self-built data of Luogu. It takes 5 minutes to complete data production using CYaRon.

 

Bare mops with modifications

 

1 # include <iostream> 2 # include <cstdio> 3 # include <cstring> 4 # include <cmath> 5 # include <algorithm> 6 # include <cstdlib> 7 # include <ctime> 8 using namespace std; 9 const int MAXN = 10001; 10 static void read (int & n) 11 {12 char c = '+'; int x = 0; bool flag = 0; 13 while (c <'0' | c> '9') {c = getchar (); if (c = '-') flag = 1 ;} 14 while (c> = '0' & c <= '9') {x = (x <1) + (x <3) + (c-48 ); c = getchar ();} 15 flag = 1? N =-x: n = x; 16} 17 int n, m; 18 int a [MAXN]; 19 struct CX 20 {21 int l, r, id, tm; // tm last change operation 22} cx [MAXN]; 23 int cxnum; 24 struct GG 25 {26 int pos, val, pre; 27} gg [MAXN]; 28 int ggnum; 29 int head [MAXN]; 30 int where [MAXN]; 31 int base; 32 int vis [MAXN]; // whether there is any change operation 33 int color [MAXN]; 34 int ans = 0; 35 int out [MAXN]; 36 int comp (const CX & a, const CX & B) 37 {38 if (where [. l] = where [B. l]) 39 return. R <B. r; 40 else 41 return where [. l] <where [B. l]; 42} 43 int calc (int x) 44 {45 if (vis [x]) 46 {47 if (-- color [a [x] = 0) 48 ans --; 49} 50 else 51 {52 if (++ color [a [x] = 1) 53 ans ++; 54} 55 vis [x] =! Vis [x]; 56} 57 void change (int p, int v) 58 {59 if (vis [p]) 60 {61 calc (p ); 62 a [p] = v; 63 calc (p); 64} 65 else 66 a [p] = v; 67} 68 69 int main () 70 {71 read (n); read (m); 72 for (int I = 1; I <= n; I ++) 73 read (a [I]), head [I] = a [I]; 74 base = sqrt (n); 75 for (int I = 1; I <= n; I ++) 76 where [I] = (I-1)/base + 1; 77 for (int I = 1; I <= m; I ++) 78 {79 char c; 80 int x, y; 81 cin> c; 82 read (x); read (y); 83 if (c = 'q') // query 84 {8 5 cxnum ++; 86 cx [cxnum]. l = x; 87 cx [cxnum]. r = y; 88 cx [cxnum]. id = cxnum; 89 cx [cxnum]. tm = ggnum; 90} 91 else 92 {93 ggnum ++; 94 gg [ggnum]. pos = x; 95 gg [ggnum]. val = y; 96 gg [ggnum]. pre = head [x]; 97 head [x] = y; 98} 99} 100 sort (cx + 1, cx + cxnum + 1, comp ); 101 int l = 1, r = 0; 102 for (int I = 1; I <= cxnum; I ++) 103 {104 for (int j = cx [I-1]. tm + 1; j <= cx [I]. tm; j ++) 105 change (gg [j]. pos, gg [j]. val); 106 for (int j = cx [I-1]. tm; j> = cx [I ]. Tm + 1; j --) 107 change (gg [j]. pos, gg [j]. pre); // This is pre, not val !!! 108 for (; l <cx [I]. l; l ++) 109 calc (l); 110 for (; l> cx [I]. l; l --) 111 call-1); 112 for (; r <cx [I]. r; r ++) 113 calc (r + 1); 114 for (; r> cx [I]. r, r --) 115 calc (r); 116 out [cx [I]. id] = ans; 117} 118 for (int I = 1; I <= cxnum; I ++) 119 printf ("% d \ n", out [I]); 120 return 0; 121}