Parse a JSON string using the dynamic tag, dynamicjson

Parse a JSON string using the dynamic tag, dynamicjson

Reference page:

Http://www.yuanjiaocheng.net/CSharp/csharprumenshili.html

Http://www.yuanjiaocheng.net/CSharp/csharp-class.html

Http://www.yuanjiaocheng.net/CSharp/csharp-variable.html

Http://www.yuanjiaocheng.net/CSharp/Csharp-data-types.html

Http://www.yuanjiaocheng.net/CSharp/cshart-value-reference-type.html

1 string jsonStr = "{\" data \ ": {\" ssoToken \ ": \" 70abd3d8a6654ff189c482fc4821368c \ ", \" account \ ": \" admin \", \ "userType \": \ "platformAdmin \", \ "realName \": \ "Super Administrator \", \ "sex \": 0, \ "sexName \": \ "male \", \ "email \": \ "alina_dong@163.com \", \ "mobile \": \ "15120757948 \", \ "createdDt \": \ "00:00:00 \", \ "updatedDt \": \ "00:00:00 \" },\ "isSuccess \": true }";

When the. Net Program receives this JSON string, you will surely think of using Newtonsoft. Json to serialize (SerializeObject) and deserialize (DeserializeObject) an object.

Example of using SerializeObject:

1 A a = new A (); 2. age = 11; 3. name = "Jack"; 4 B B = new B (); 5 B. sex = "Man"; 6 // B. money = 12; 7. B = B; 8 string str = Newtonsoft. json. jsonConvert. serializeObject (a); 9 10 output result: {"age": 11, "name": "Jack", "B": {"sex": "Man ", "money ":""}}

DeserializeObject example:

1 string jsonStr = @ "{" age ": 11," name ":" Jack "," B ": {" sex ":" Man "," money ": ""} "; 2 var a = Newtonsoft. json. jsonConvert. deserializeObject <A> (jsonStr); 3 4 Results:. age = 11 ;.......

Now let's get down to the point. How can we use dynamic to parse a Json string?

1 string jsonStr = "{\" data \ ": {\" ssoToken \ ": \" 70abd3d8a6654ff189c482fc4821368c \ ", \" account \ ": \" admin \", \ "userType \": \ "platformAdmin \", \ "realName \": \ "Super Administrator \", \ "sex \": 0, \ "sexName \": \ "male \", \ "email \": \ "alina_dong@163.com \", \ "mobile \": \ "15120757948 \", \ "createdDt \": \ "00:00:00 \", \ "updatedDt \": \ "00:00:00 \"}, \ "isSuccess \": true} "; 2 var loginInfo = JsonConvert. deserializeObject <dynamic> (jsonStr); 3 var user = loginInfo. data; 4 string ssoToken = user. ssoToken; 5 string account = user. account;

In this way, you do not need to create loginInfo. the user can parse JSON as well, and no error will be reported because of the added fields.

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