Perform binary, octal, hexadecimal, and decimal conversion in Java

Convert decimal to hexadecimal:

Integer. tohexstring (int I)

Decimal to octal

Integer. tooctalstring (int I)

Convert decimal to binary

Integer. tobinarystring (int I)

Hexadecimal to decimal

Integer. valueof ("ffff", 16). tostring ()

Octal to decimal

Integer. valueof ("876", 8). tostring ()

Convert binary to decimal

Integer. valueof ("0101", 2). tostring ()


Is there any way to directly convert 2, 8, and 16 to 10?

Java. Lang. Integer class

Parseint (string S, int Radix)

Use the base number specified by the second parameter to resolve the string parameter to a signed integer.

Examples from JDK:

Parseint ("0", 10) returns 0

Parseint ("473", 10) returns 473

Parseint ("-0", 10) returns 0

Parseint ("-FF", 16) returns-255

Parseint ("1100110", 2) returns 102

Parseint ("2147483647", 10) returns 2147483647

Parseint ("-2147483648", 10) returns-2147483648

Parseint ("2147483648", 10) throws a numberformatexception

Parseint ("99", 8) throws a numberformatexception

Parseint ("Kona", 10) throws a numberformatexception

Parseint ("Kona", 27) returns 411787.


How to Write (2, 8, 16) in hexadecimal conversion without Algorithms

Integer. tobinarystring

Integer. tooctalstring

Integer. tohexstring

Example 1:

public class Test{  public static void main(String args[]){   int i=100;   String binStr=Integer.toBinaryString(i);   String otcStr=Integer.toOctalString(i);   String hexStr=Integer.toHexString(i);   System.out.println(binStr);

Example 2:

public class TestStringFormat {  public static void main(String[] args) {   if (args.length == 0) {      System.out.println("usage: java TestStringFormat <a number>");      System.exit(0);   }   Integer factor = Integer.valueOf(args[0]);   String s;   s = String.format("%d", factor);   System.out.println(s);   s = String.format("%x", factor);   System.out.println(s);   s = String.format("%o", factor);   System.out.println(s);  }}