Php calculates the number of days between two dates _ PHP Tutorial

Php calculates the number of days between two dates. This article will introduce to you in detail the example of the number of days between two dates calculated by php. for your reference, we generally use strtotime to convert the date and then calculate it, this article will introduce to you in detail the example of the number of days between two dates calculated by php. for your reference, we generally use strtotime to convert the date and then calculate it, this can be accurate to minutes and seconds.

Example 1

Convert the date directly

The code is as follows:
Function daysbetweendates ($ date1, $ date2 ){ $ Date1 = strtotime ($ date1 ); $ Date2 = strtotime ($ date2 ); $ Days = ceil (abs ($ date1-$ Date 2)/86400 ); Return $ days; }

Example 2

The code is as follows:
Functionmaketime ($ date) { List ($ year, $ month, $ day) = explode ('-', $ date ); Returnmktime (0, 0, 0, $ month, $ day, $ year ); } $ Date1 = '2017-01-08 '; $ Date2 = '2017-03-01 '; $ D = (maketime ($ date2)-maketime ($ date1)/(24x3600 ); Echo 'difference $ d Day '; ?>

Example 3

PHP calculates the year, month, week, and number of days between two dates.

The code is as follows:

Function format ($ a, $ B ){ // Check the size of two dates. the default value is "first small" and "later". if the former value is greater than the latter value, the positions are exchanged to ensure the former value is greater than the former value. If (strtotime ($ a)> strtotime ($ B) list ($ a, $ B) = array ($ B, $ ); $ Start = strtotime ($ ); $ Stop = strtotime ($ B ); $ Extend = ($ stop-$ start)/86400; $ Result ['extends '] = $ extend; If ($ extend <7) {// returns the number of days if it is less than 7 days $ Result ['Daily '] = $ extend; } Elseif ($ extend <= 31) {// The number of weeks is returned if it is less than 28 days. because the leap year meets If ($ stop = strtotime ($ a. '+ 1 month ')){ $ Result ['monthly '] = 1; } Else { $ W = floor ($ extend/7 ); $ D = ($ stop-strtotime ($ a. '+'. $ w. 'Week ')/86400; $ Result ['weekly '] = $ w; $ Result ['Daily '] = $ d; } } Else { $ Y = floor ($ extend/365 ); If ($ y> = 1) {// if it is more than one year $ Start = strtotime ($ a. '+'. $ y. 'year '); $ A = date ('Y-m-D', $ start ); // Determine whether it has been a year. if not, subtract it. If ($ start> $ stop ){ $ A = date ('Y-m-D', strtotime ($ a. '-1 month ')); $ M = 11; $ Y --; } $ Extend = ($ stop-strtotime ($ a)/86400; } If (isset ($ m )){ $ W = floor ($ extend/7 ); $ D = $ extend-$ w * 7; } Else { $ M = isset ($ m )? $ M: round ($ extend/30 ); $ Stop> = strtotime ($ a. '+'. $ m. 'month ')? $ M: $ m --; If ($ stop> = strtotime ($ a. '+'. $ m. 'month ')){ $ D = $ w = ($ stop-strtotime ($ a. '+'. $ m. 'month')/86400; $ W = floor ($ w/7 ); $ D = $ d-$ w * 7; } } $ Result ['early '] = $ y; $ Result ['monthly '] = $ m; $ Result ['weekly '] = $ w; $ Result ['Daily '] = isset ($ d )? $ D: null; } Return array_filter ($ result ); } Print_r (format ('2017-10-1 ', '2017-12-15 ')); ?>

Worker calculates the number of days between two dates. for your reference, we generally use strtotime to convert the date and then calculate it ,...