Php date function date_parse_from_format

The general practice is to split the string into a function, and then obtain the required data, such as the number of days, month, and year, and then combine them to use the strtotime function for conversion.

If you encounter a log file date format such as [29/Feb/2012: 23: 59: 31 + 0800], convert it to a timestamp, what would you do?

The general practice is to split the string into a function, and then obtain the required data, such as the number of days, month, and year, and then combine them to use the strtotime function for conversion.

Timestamp. Is there a more concise way? The answer is yes!

The php date function date_parse_from_format () can retrieve what you want from the specified date format.

Date_parse_from_format ($ format, $ date)

$ Format // The format of the date, for example, 29/Feb/2012: 23: 59: 31, is d/M/Y: H: I: s.

$ Date // the original time character, for example, 29/Feb/2012: 23: 59: 31

Example:

$ Arr = date_parse_from_format ("d/M/Y: H: I: s", "29/Feb/2012: 23: 59: 31"); // execute the function

Return format:

Array
	(
	[Year] = & gt; 2012
	[Month] => 2
	[Day] => 29
	[Hour] => 23
	[Minute] => 59
	[Second] => 31
	[Fraction] =>
	[Warning_count] => 0
	[Warnings] => Array
	(
	)
	[Error_count] => 0
	[Errors] => Array
	(
	)
	[Is_localtime] =>
	)

Then we can use strtotime to convert the time to the timestamp!

Note: date_parse_from_format can be used only in php5.3 and later versions. if your version is not high enough, it doesn't matter.

You can use the same method as follows:

If (! Function_exists ('date _ parse_from_format ')){
Function date_parse_from_format ($ format, $ date ){
$ DMask = array (
'H' => 'hour ',
'I' => 'Minute ',
'S '=> 'second ',
'Y' => 'year ',
'M' => 'month ',
'D' => 'day'

);
$ Format = preg_split ('//', $ format,-1, PREG_SPLIT_NO_EMPTY );
$ Date = preg_split ('//', $ date,-1, PREG_SPLIT_NO_EMPTY );
Foreach ($ date as $ k => $ v ){
If ($ dMask [$ format [$ k])
$ Dt [$ dMask [$ format [$ k]. = $ v;
}
Return $ dt;
}
}