PHP does not need to upload images or download images,

PHP does not need to upload images or download images,

The php ajax implementation code for the function of uploading images and downloading images without refreshing is as follows:

<Meta charset = "UTF-8"> <form id = "uploadForm"> <p> specify the file name: <input type = "text" name = "filename" value = ""/> </p> <p> upload a file: <input type = "file" name = "photo" onchange = "showPreview (this) "class =" file "/>  </p> <input type =" button "value =" Upload "onclick =" doUpload () "/> </form> <script src =" http://www.haoyunyun.cn/jquery.js "> </script> <script> function doUpload () {var formData = new FormData ($ (" # uploadForm ") [0]); $. ajax ({url: 'submit. php ', type: 'post', data: formData, async: false, cache: false, contentType: false, processData: false, success: function (returndata) {alert (returndata) ;}, error: function (returndata) {alert (returndata );}});} </script> <script type = "text/javascript"> function showPreview (source) {var file = source. files [0]; if (window. fileReader) {var fr = new FileReader (); fr. onloadend = function (e) {document. getElementById ("portrait "). src = e.tar get. result;}; fr. readAsDataURL (file) ;}</script>

Submit. php

<? Php if ($ _ FILES ['photo'] ['error']> 0) {echo "File Upload Failed"; die;} $ dir = '. /photo/'; $ type = substr ($ _ FILES ['photo'] ['name'], strrpos ($ _ FILES ['photo '] ['name'], '. '); $ filename = time (). rand (1000,9999 ). $ type; if (is_uploaded_file ($ _ FILES ['photo '] ['tmp _ name']) {move_uploaded_file ($ _ FILES ['photo '] ['tmp _ name'], $ dir. $ filename); echo "Upload succeeded";} else {echo "File Upload Failed ";}

Traverse database data

<? Php header ("content-type: text/html; charset = UTF-8"); $ link = mysql_connect ("127.0.0.1", 'root', 'root '); mysql_select_db ("php9", $ link); mysql_query ("set names utf8"); // query the total number of data records $ SQL = "select count (id) as count from upload "; $ arr = mysql_query ($ SQL); $ result = mysql_fetch_assoc ($ arr); // obtain the total number of items $ size = $ result ['Count']; // two pieces of data are displayed on each page $ length = 6; // calculate the number of pages $ pages = ceil ($ size/$ length ); $ page = isset ($ _ GET ['page'])? $ _ GET ['page']: 1; if ($ page <= 0) {$ page = 1;} if ($ page> $ pages) {$ page = $ pages;} // The number of data entries starting with $ start = ($ page-1) * $ length; $ SQL = "select * from upload limit $ start, $ length"; $ res = mysql_query ($ SQL);?> <Center> <table border = "1"> <div> <? Php while ($ a = mysql_fetch_assoc ($ res) {?> <Ul> <li> <? Php echo $ a ['id']?> </Li> <? Php echo $ a ['username']?> </Li> <a href = "photo. php" rel = "external nofollow">  "Width =" 80px "> </a> </li> <? Php echo $ a ['sc1']?> </Li> <a href = "photo3.php? Dir = <? Php echo $ a ['dir']?> "Rel =" external nofollow "> download </a> <a href =" photo4.php? Id = <? Php echo $ a ['id']?> & Dir = <? Php echo $ a ['dir']?> "Rel =" external nofollow "> Delete </a> </li> </ul> <? Php }?> </Div> </table> <a href = "photo2.php? Page = 1 "rel =" external nofollow "> homepage </a> <a href =" photo2.php? Page = <? Php echo $ page-1?> "Rel =" external nofollow "> previous page </a> <a href =" photo2.php? Page = <? Php echo $ page + 1?> "Rel =" external nofollow "> next page </a> <a href =" photo2.php? Page = <? Php echo $ pages?> "Rel =" external nofollow "> last page </a> </center> <style> * {margin: 0; padding: 0 ;}div {width: 900px; height: 850px; border: 1px solid #28a4c9; margin: auto;} img {width: 200px; height: 130px; margin-left: 100px;} ul {width: 400px; height: 300px; float: left;} li {list-style: none; margin-left: 10px;} </style>

Download Code

 <?php   header("content-type:text/html;charset=utf-8");   $dir=$_GET['dir'];   $filename=substr($dir,strrpos($dir,'/')+1);   header("Content-type:image");   header("content-disposition:attachment;filename=$filename");   readfile($dir);   ?> 

The above is a small Editor to introduce you to the function of uploading images and downloading images without refreshing ajax in PHP. I hope it will be helpful to you. If you have any questions, please leave a message for me, the editor will reply to you in a timely manner. Thank you very much for your support for the help House website!